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ddd [48]
3 years ago
5

What is the correct definition of speed?

Chemistry
1 answer:
docker41 [41]3 years ago
5 0

Answer:

B

Explanation:

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The molality of a solution containing 8.1 moles of solute in 4,847 g of solvent is _____. 1.7m 598m 39m 0.17m
Hitman42 [59]
When molality = no.of moles of solute/weight Kg of solvent

and when we have the no. of moles of solute = 8.1 moles
and the weight Kg of the solvent =4847 g /1000 = 4.847 Kg
so by substitution :
Molarity = 8.1m / 4.847Kg = 1.67 M
4 0
4 years ago
Read 2 more answers
In this chemical formula: 3NH4 (ammonium) This chemical formula means there are 3 _____________ ___________, and 4 __________ __
seropon [69]

Answer:

hope it helped you

Explanation:

3 atoms of nitrogen and 4 atoms of hydrogen in each molecule

5 0
3 years ago
Insoluble molecular compounds break apart into atoms when added to water.<br> True<br> O False
masha68 [24]

Answer:

False.

This is false because, no chemical reaction could possibly happen.

But in case of sodium it is highly reactive with water.......... so there will be a chemical reaction.

but as sodium is not a insoluble molecular compound this is not applicable to the situation.

8 0
3 years ago
Consider the following multistep reaction:
chubhunter [2.5K]

The question is incomplete, here is the complete question:

Consider the following multistep reaction:

C+D⇌CD (fast)

CD+D→CD₂ (slow)

CD₂+D→CD₃ (fast)

C+3D→CD₃

Based on this mechanism, determine the rate law for the overall reaction.

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[C][D]^2

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

C+3D\rightarrow CD_3

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  C+D\rightleftharpoons CD;\text{ (fast)}

<u>Step 2:</u>  CD+D\rightarrow CD_2;\text{(slow)}

<u>Step 3:</u>  CD_2+D\rightarrow CD_3;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[CD][D]           ......(1)

As, [CD] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for CD from step 1, we get:

K=\frac{[CD]}{[C][D]}

[CD]=K[C][D]

Putting the value of [CD] in equation 1, we get:

\text{Rate}=k.K[C][D]^2\\\\\text{Rate}=k'[C][D]^2  

Hence, the rate law for the reaction is \text{Rate}=k'[C][D]^2

5 0
3 years ago
What happens to PH of basic solution as you add water
Arlecino [84]

Answer:

to fall towards 7, making the solution less alkaline as more water is added.

8 0
2 years ago
Read 2 more answers
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