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Elanso [62]
2 years ago
12

1. How do organisms maintain homeostasis?

Chemistry
1 answer:
Alex_Xolod [135]2 years ago
6 0

Answer:

Maintenance of homeostasis usually involves negative feedback loops. These loops act to oppose the stimulus, or cue, that triggers them.

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The density of the fat tristearin is 0.95 g cm−3 . Calculate the change in molar Gibbs energy of tristearin when a deep-sea crea
KatRina [158]

The formula for the change in Gibbs energy of a solid is:

ΔG = Vm ΔP

where, ΔG is change in Gibbs, Vm is molar volume, ΔP is change in pressure

ΔP = P(final) – P(initial)

P(final) = 1 atm = 101325 Pa

P(initial) = ρ_water *g *h = (1030 kg/m^3) * 9.8 m/s^2 * 2000 m = 20188000 kg m/s^2 = 20188000 Pa

Vm = (950 kg/m^3) * (1000 mol / 891.48 kg) = 1065.64 mol/m^3

 

So,

ΔG = (1065.64 mol/m^3) * (101325 Pa - 20188000 Pa)

<span>ΔG = -21405164347 J = -21.4 GJ</span>

8 0
3 years ago
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×
Anuta_ua [19.1K]

Answer:

Kc=~1.49x10^3^4}

Explanation:

We have the reactions:

A: N_2_(_g_) + O_2_(_g_)  2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9

Our <u>target reaction</u> is:

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)

We have NO_(_g_) as a reactive in the target reaction and  NO_(_g_) is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

Then if we add reactions A and B we can obtain the target reaction, so:

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9

For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}

Kc=~1.49x10^+^3^4}

3 0
3 years ago
The molar mass of aniline is 93 g/mol. what is its molecular formula
Mashutka [201]

Answer:

Molecular formula of aniline is C6H5NH2.

Explanation:

As we know, molecular mass can be calculated as

Molar mass =  C6H5NH2

Molar mass = (6*12)+(1*7)+(28)

Molar mass  = 93 g/mol

4 0
3 years ago
How many hydrogen atoms are in 4.40 mol of ammonium sulfide
katrin2010 [14]
 The number  of hydrogen  atoms  that are  in 4.40  mol  of ammonium sulfide is  2.12 x10^25  atoms

      calculation
 find the number of moles  of Hydrogen  in ammonium sulfide  (NH4)2S

that is  4.40  x  number of hydrogen atoms in (NH4)2S ( 4x2= 8  atoms)

moles is  therefore=  4.40  x8= 35.2  moles

by  use of  Avogadro's law  constant

that is  1mole =  6.02 x10^23 atoms
         35.2  moles=?

by  cross multiplication
  {35.2 moles x 6.02 x10^23} /1 mole  = 2.12  x10^25  atoms
5 0
3 years ago
Read 2 more answers
During the combustion of a peanut that weighed 0.341 g, the temperature of the 100 mL of water in the calorimeter rose from 23.4
blondinia [14]

Answer:

119 kCal per serving.

Explanation:

The heat energy necessary to elevates water's temperature from 23.4°C to 37.9°C can be calculated by the equation below:

Q = mcΔT

Q: heat energy

m: mass in g

c: specific heat capacity in cal/g°C

ΔT = temperature variation in °C

m is the mass of water, considering the density of water to be 1g/mL, 100 mL of water weights  100g. Therefore:

Q = 100 g x 1.00 cal/g°C x (37.9 - 23.4)°C

Q = 1450 cal

1450 cal ____ 0.341 g peanuts

x             ____  28 g peanuts

x = 119061.58 cal

This means that the cal from fat per serving of peanuts is at least 119 kCal.

3 0
3 years ago
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