"CH4" is the one gas among the choices given in the question that <span>would have the fastest rate of effusion. The correct option among all the options that are given in the question is the second option or option "B". I hope that this is the answer that has actually come to your great help.</span>
1. Potential Energy is stored energy a object has when it's not moving.
2. Potential Energy is it's highest on the first stage because as you see the roller coaster is bout to go down the tract which is going to higher the kinetic energy and lower the potential energy.
3. Kinetic Energy is the amount of energy a object has when it's in motion or moving.
4. Kinetic Energy is it's highest in the third stage after it's gone down the tract and potential energy fully decreased and it's at zero.
Remember that potential energy is stored energy so when a object is not moving in this case the roller coaster isn't moving on the first stage when its bout to go down the roller coaster. Kinetic energy is the amount of energy a object has when it's in motion so in this case the third stage would have the highest example of Kinetic energy because it's fully in motion and has no potential energy.
Answer:
protons and neutrons
Explanation:
protons and neutrons is equal to mass number
Answer: Option (a) is the correct option.
Explanation:
In order to travel, sound does need a medium. The more closer the particles of a medium, the better sound can travel through it. Therefore, in solids sound travels very quickly because in solids particles are closer to each other. As a result, they can easily transmit the energy from one particle to another.
Thus, it becomes easier for sound to travel through it. On the other hand, in solids sound can travel in both longitudinal and transverse waves.
Hence, out of the given options, sound travels in transverse waves requires a medium to travel through is the correct option.
this is a dilution question where a certain volume is taken from a more concentrated solution and diluted to make a solution with a lower concentration.
the dilution forumla is as follows
c1v1 = c2v2
where c1 is concentration and v1 is volume of the more concetrated solution
c2 is concentration and v2 is volume of the diluted solution
substituting the values in the equation
18.0 M x V = 0.126 M x 16.5 L
V = 0.1155 L
volume of 115.5 mL is taken from the 18.0 M solution and diluted upto 16.5 L solution.
