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fredd [130]
3 years ago
5

How many of are in 1g​

Chemistry
1 answer:
-BARSIC- [3]3 years ago
8 0
1g=128fl.oz(fluid ounces)
1g=4qt (quarts)
3.785L(liters)=1g
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Determine the number of moles of hydrogen atoms in each sample.
schepotkina [342]
The answer is going to be d
8 0
3 years ago
How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
levacccp [35]

Answer:

Total moles of ions are released in water are 1.131\times 10^{-5} mol.

Explanation:

Mass of calcium nitrate = 6.18\times 10^{-4} g

Molar mass of calcium nitrate = 164 g/mol

Moles of calcium nitrate = \frac{6.18\times 10^{-4} g}{164 g/mol}=3.77\times 10^{-6} mol

Ca(NO_3)_2(aq)\rightarrow Ca^{2+}(aq)+2NO_3^{-}(aq)

According to reaction, 1 mole of calcium nitrate gives 1 mole of calcium ions, then 3.77\times 10^{-6} moles of calcium nitrate will give:

1\times 3.77\times 10^{-6} mol=3.77\times 10^{-6} mol of calcium ions

According to reaction, 1 mole of calcium nitrate gives 2 mole of nitrate ions, then 3.77\times 10^{-6} moles of calcium nitrate will give:

2\times 3.77\times 10^{-6} mol=7.54\times 10^{-6} mol of nitrate ions

Total moles of ions are released :

3.77\times 10^{-6} mol+7.54\times 10^{-6} mol=11.31\times 10^{-6} mol\approx 1.131\times 10^{-5} mol

6 0
3 years ago
How much heat does it take to increase the temperature of 2.70 mol of an ideal gas by 30.0 K near room temperature if the gas is
Mnenie [13.5K]

Answer:

1683.6J

Explanation:

Given:

n= no. Of mol= 2.70 mol

T= Temperature= 30.0 K

Q= n Cv × ∆T .........eqn(1)

Where CV= molar heat capacity=5/2R for diatomic particle ,such as H2

CV= molar heat capacity=3/2R for diatomic, such as H

R= gas constant= 8.314 J/mol.K

Q= heat energy

For a diatomic molecules

Q= n Cv × T

But

Cv= molar heat capacity=5/2R = 5/2(8.314)=20.785

CV= 20.785

. ∆T= Temperature= 30.0 K

Then substitute the values into the eqn(1)

Q= 2.70 × 5/2(8.314) × 30

Q= 2.70 × 20.785 × 30

=1683.6J

6 0
3 years ago
Sodium is a larger atom than lithium. List three reasons why this is true.
just olya [345]

Answer:

It is present in third period that's why its valance electrons are present in 3rd energy level.

Its atomic number is greater than lithium when compared in group wise.

There are more electrons in sodium to shield the outer valance electron thus nuclear attraction becomes weak and size increase.

Explanation:

The size of sodium is greater than lithium because atomic number of sodium is 11 and lithium is 3. Both are present in first group but sodium is present down to the lithium. As we move from top to bottom in a group atomic size increases with addition of electrons. The nuclear effect become weaker on valance electrons and atomic size increase. Same time shielding effect is also produces which shield the outer electrons from the influence of nucleus. While in case of lithium less electrons are present to shield the valance electrons.

As we note the position of both elements along period. The sodium is present in third period while lithium is present in second period. So, in case of sodium third energy level is involved. That's why its size is greater than lithium.

8 0
3 years ago
Please explain this to me, it's taking forever for me!
liubo4ka [24]

Answer:

civic cgvvbbbibbbnn bnnnn

5 0
3 years ago
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