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xeze [42]
3 years ago
6

What is one property that is different between water and oil? *

Chemistry
1 answer:
Arlecino [84]3 years ago
3 0
Oil is less dense than water, so the difference would be its density. Water is a good solvent, which means It can dissolve other substances.
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Which example is a trace fossil? {A} dinosaur egg {B} dinosaur footprint {C} dinosaur bone {D} shark tooth
viktelen [127]

dinosaur footprint

Explanation:

A dinosaur footprint is an example of a trace fossil. A trace fossil is a type of fossil that shows the activities of organisms that lived in the past.

  • Fossils are the preserved remains of organisms that lived several years ago.
  • Fossils are usually found in sedimentary rocks and thick layers of ice in temperate and polar regions.
  • Body fossils are the remains of the body parts of an organism that has been preserved. They can be skeletal parts, teeth, eggs e.t.c
  • A trace fossil shows the preserved remains of the activities of an organism.
  • They can be fingerprints, burrows and borings, feccal pellets e.t.c

Learn more":

fossils and evolution brainly.com/question/12790206

#learnwithBrainly

5 0
3 years ago
Read 2 more answers
Round each number to four significant figures
ira [324]

Answer:

a.

84,791 » 8479

b.

256.75 » 256.8

c.

431,801 » 4318

d.

0.00078100 » 0.0007810

Explanation:

.

5 0
3 years ago
A reaction of 17.0 g of ammonia with 26.6 g of chlorine gas
Elena-2011 [213]

Answer: if doing it on ck-12 the answer is 40.1

Explanation:

4 0
2 years ago
During oxidation, which of the following is true? A. Electrons are gained, so the oxidation number increases. B. Electrons are g
EastWind [94]

Oxidation is when the overall charge (or oxidation number) increases.  The only way to increase an oxidation number is to lose an electron, thereby making the negative charges less.  The correct answer is C.

6 0
3 years ago
Read 2 more answers
What is the excess reactant in the combustion of 23 g of methane in the open atmosphere?
Marta_Voda [28]

Answer : The excess reactant in the combustion of methane in opem atmosphere is O_{2} molecule.

Solution : Given,

Mass of methane = 23 g

Molar mass of methane = 16.04 g/mole

The Net balanced chemical reaction for combustion of methane is,

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

First we have to calculate the moles of methane.

\text{ Moles of methane}=\frac{\text{ Given mass of methane}}{\text{ Molar mass of methane}} = \frac{23g}{16.04g/mole} = 1.434 moles

From the above chemical reaction, we conclude that

1 mole of methane react with the 2 moles of oxygen

and 1.434 moles of methane react to give \frac{2moles\times 1.434moles}{1moles} moles of oxygen

The Moles of oxygen = 2.868 moles

Now we conclude that the moles of oxygen are more than the moles of methane.

Therefore, the excess reactant in the combustion of methane in open atmosphere is O_{2} molecule.


6 0
3 years ago
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