Answer:
The answer to your question is below
Explanation:
Data
pOH = 5.9
a) [OH⁻] = ?
pOH measures the [OH⁻]
Formula
pOH = -log[OH⁻]
-Substitution
5.9 = -log[OH⁻]
[OH⁻] = antilog (-5.9)
-Result
[OH⁻] = 1.26 x 10⁻⁶ M
b) [H₃O⁺]
pH + pOH = 14
-Solve for pH
pH = 14 - pOH
-Substitution
pH = 14 - 5.9
-Result
pH = 8.1
-Calculate [H₃O⁺]
pH = -log[H₃O⁺]
-Substitution
8.1 = -log[H₃O⁺]
[H₃O⁺] = antilog(-8.1)
-Result
[H₃O⁺] = 7.9 x 10⁻⁹ M
c) This solution is alkaline because the pH is higher than 7.
That is called the<u> variable</u> because it varies/changes in the experiment,
it's like x in algebra (with more than one placeholder), if it changes, it normally gives you a different result
The solution to your problem is as follows:
<span>2 KClO3 → 2 KCl + 3 O2
</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole
62.6/74.6 = 0.839 moles KCl produced
0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
</span>
Therefore, there are <span>40.27g of O2 produced during the reaction.
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
Hello!
a gas thermometer measure temperature by measuring the pressure of a gas inside the fixed volume container a thermometer reads a pressure of 248 torr at 0 degrees Celsius what is the temperature when the thermometer reads a pressure of 345 torr
We have the following information:
P1 (initial pressure) = 248 torr
T1 (initial temperature) = 0 ºC (in Kelvin)
TK = TºC + 273.15 → TK = 0 + 273.15 → T1 (initial temperature) = 273.15 K
P2 (final pressure) = 345 torr
T2 (final temperature) = ? (in Kelvin)
According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, then we will have the following formula:






If you want the solution in Celsius Temperature, we have:
TC = TK - 273.15
TC = 380 - 273.15
TC = 106.85 → Temperature = 106.85 ºC
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I Hope this helps, greetings ... Dexteright02! =)