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mrs_skeptik [129]
3 years ago
10

What type of reaction is this? N2 + 3H2 2NH3

Chemistry
1 answer:
Levart [38]3 years ago
7 0

Answer:

It is a combination reaction; nitrogen and hydrogen combine to form ammonia.

Explanation:

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A solution has pOH 5.9
QveST [7]

Answer:

The answer to your question is below

Explanation:

Data

pOH = 5.9

a) [OH⁻] = ?

pOH measures the [OH⁻]

Formula

pOH = -log[OH⁻]

-Substitution

5.9 = -log[OH⁻]

[OH⁻] = antilog (-5.9)

-Result

[OH⁻] = 1.26 x 10⁻⁶ M

b) [H₃O⁺]

pH + pOH = 14

-Solve for pH

pH = 14 - pOH

-Substitution

pH = 14 - 5.9

-Result

pH = 8.1

-Calculate [H₃O⁺]

pH = -log[H₃O⁺]

-Substitution

8.1 = -log[H₃O⁺]

[H₃O⁺] = antilog(-8.1)

-Result

[H₃O⁺] = 7.9 x 10⁻⁹ M

c) This solution is alkaline because the pH is higher than 7.

6 0
3 years ago
Read 2 more answers
What's the word called part of an experiment that changes to observe an outcome?
Fiesta28 [93]
That is called the<u> variable</u> because it varies/changes in the experiment,

it's like x in algebra (with more than one placeholder), if it changes, it normally gives you a different result
8 0
3 years ago
When heated, KClO3 decomposes into KCl and O2. KClO3--&gt; 2KCl+ 3O . If this reaction produced 62.6 g of KCl, how much O2 was p
Vladimir [108]
The solution to your problem is as follows:

 <span>2 KClO3 → 2 KCl + 3 O2 

</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole 

62.6/74.6 = 0.839 moles KCl produced 

0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
</span>
Therefore, there are <span>40.27g of O2 produced during the reaction.
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.


5 0
3 years ago
a gas thermometer measure temperature by measuring the pressure of a gas inside the fixed volume container a thermometer reads a
sdas [7]

Hello!

a gas thermometer measure temperature by measuring the pressure of a gas inside the fixed volume container a thermometer reads a pressure of 248 torr at 0 degrees Celsius what is the temperature when the thermometer reads a pressure of 345 torr

We have the following information:

P1 (initial pressure) = 248 torr

T1 (initial temperature) = 0 ºC (in Kelvin)

TK = TºC + 273.15 → TK = 0 + 273.15 → T1 (initial temperature) = 273.15 K

P2 (final pressure) = 345 torr

T2 (final temperature) = ? (in Kelvin)

According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, then we will have the following formula:

\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2}

\dfrac{248}{273.15} = \dfrac{345}{T_2}

248*T_2 = 345*273.15

248\:T_2 = 94236.75

T_2 = \dfrac{94236.75}{248}

T_2 = 379.9868952... \to \boxed{\boxed{T_2 \approx 380\:K}}\end{array}}\qquad\checkmark

If you want the solution in Celsius Temperature, we have:

TC = TK - 273.15

TC = 380 - 273.15

TC =  106.85 → Temperature = 106.85 ºC

_______________________________

I Hope this helps, greetings ... Dexteright02! =)

6 0
3 years ago
100 PNTS ANSWER ASAP PLZ The density of a particular small rubber ball is 1.1 g/cm3. It was dropped into a 100 mL beaker filled
AlekseyPX

Answer:

a

Explanation:

3 0
3 years ago
Read 2 more answers
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