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Art [367]
3 years ago
10

What is a transverse wave?

Physics
1 answer:
Tema [17]3 years ago
5 0
The answer is C. they travel perpendicular to the direction of energy
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The speed of light in benzene is 2.00×108 m/s. what is the index of refraction of benzene?
Klio2033 [76]
The index of refraction of a material is the ratio between the speed of light in vacuum, c, and the speed of light in that material, v:
n= \frac{c}{v}
where the speed of light in vacuum is c=3 \cdot 10^8 m/s. The speed of light in benzene is v=2.00 \cdot 10^8 m/s, so we can use the previous relationship to find the refractive index of benzene:
n= \frac{3 \cdot 10^8 m/s}{2.00 \cdot 10^8 m/s}=1.5
7 0
3 years ago
An official act by the President forgiving a person convicted of a crime and
Igoryamba

Answer:

Pardon

Explanation:

Using the fundamental laws of mass-energy conservation. We can determine that the photon particle is fundamental and delivers the energy required to change the mass of an object into energy.

7 0
3 years ago
Read 2 more answers
A ruler vibrates 70 times in 20 seconds.what is the frequency of its vibration
Bad White [126]

Answer:

we know that that frequency= n/t

= 70/20

= 3.5 Hertz

Explanation:

i think that the answer

8 0
3 years ago
What Current is drawn by a vacuum cleaner from 120 V circuit having a resistance of 28
Ostrovityanka [42]

Answer:

4.3A

Explanation:

V=IR

120=I×28

I=120/28

=4.3

hope this helps

please like and Mark as brainliest

5 0
3 years ago
Calculate the work done (in J) by a 90.0 kg man who pushes a crate 4.25 m up along a ramp that makes an angle of 20.0° with the
Mrrafil [7]

Answer:

W = 3.4x0³ J.

Explanation:

The work done by the man is given by the following equation:

W = F_{t}\cdot d     (1)

<em>where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.</em>  

We need to find first the total force Ft, which is:

Ft = Fm + W

<em>where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°.  </em>

F_{t} = Fm + W = 500 N + 90.0 kg*9.81 m/s^{2} * sin(20.0) = 802.0 N

Hence, the work is:

W = 802.0 N \cdot 4.25 m = 3.4 \cdot 10 ^{3} J  

Therefore, the work done by the man is 3.4x10³ J.  

I hope it helps you!      

8 0
3 years ago
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