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algol [13]
3 years ago
8

An object is in free fall. After 10 seconds calculate the distance fallen?

Physics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

D.490.5\ m

Explanation:

We\ are\ given\ that,\\Acceleration\ due\ to\ gravity\ (On\ Earth)=9.81\ m/s^2\\Initial\ Velocity\ of\ the\ body=0\ m/s\\Time\ taken=10\ seconds\\Hence,\\From\ the\ Second\ Equation\ of\ Motion:\\S=ut+\frac{1}{2}at^2\\By\ reconstructing\ the\ equation:\\S=ut+ \frac{1}{2}gt^2\\Hence, here\\S=0*10+\frac{1}{2}*9.81*10^2\\S=\frac{1}{2}*981\\S=490.5\ m

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The wires that will have the least resistance is :
C. A short thick wire
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3 years ago
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solniwko [45]

Answer:

0.13 seconds

Explanation:

Since 1 Km = 0.621 miles

3.84 x 105 km = 3.84 x 105 × 0.621 = 23846.4 miles

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3 0
3 years ago
Interactive LearningWare 4.1 reviews the approach taken in problems such as this one. A 1800-kg car is traveling with a speed of
Lubov Fominskaja [6]

Answer:

F= 4788 N

Explanation:

Because the car moves with uniformly accelerated movement we apply the following formula:

vf²=v₀²+2*a*d Formula (1)

Where:  

d:displacement in meters (m)  

v₀: initial speed in m/s    

vf: final speed in m/s  

a: acceleration in m/s²

Data

d=36.9 m

v₀=14.0 m/s m/s    

vf= 0  

Calculating of the acceleration of the car

We replace dta in the formula (1)

vf²=v₀²+2*a*d

(0)²=(14)²+2*a*(36.9)

-(14)²= (73.8) *a

a= - (196) /  (73.8)

a= - 2.66 m/s²

Newton's second law of the car in direction  horizontal (x):

∑Fx = m*ax Formula (2)

∑F : algebraic sum of the forces in direction x-axis (N)

m : mass (kg)

a : acceleration  (m/s²)

Data

m=1800 Fkg

a= - 2.66 m/s²

Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :

We replace data in the formula (2)

-F= (1800 kg) * ( -2.66 m/s² )

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6 0
3 years ago
Copper wire is 1. 9 mm in diameter and carries a current of 20 a. What is the electric field stregnth inside this wire?
Tju [1.3M]

The electric field strength will be 0.6252 V/m. It is the strength at which the field is created by charges.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge.

The electric field strength is found as;

\rm E = \frac{I \rho }{A} \\\\ \rm E = \frac{20  \times 1.68 \times 10^{-8} }{ (0.6385 \times 10^{-6}} \\\\ E= 0.5262 \  V/m

Hence, the electric field strength will be 0.6252 V/m.

To learn more about the electric field strength, refer to the link;

brainly.com/question/4264413

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