The other 2 angles of given right angles are 61.93° and 28.072°, if a triangle with side lengths 8, 15, and 17 is a right triangle by the converse of the Pythagorean Theorem.
Step-by-step explanation:
The given is,
Right angled triangle,
Side lengths are 8, 15, and 17
Step:1
The given triangle is right angle triangle by the converse of Pythagorean theorem, so the trigonometric ratio,
Ref the attachment,
For angle a,
...................................................(1)
Where, Opp - 8
Hyp - 17
From equation (1),
= 0.470588
(0.470588)
a = 28.072°
For angle b,
...................................................(1)
Where, Opp - 15
Hyp - 17
From equation (1),
= 0.882352
(0.882352)
b = 61.93°
Step:2
Check for solution for right angle triangle,
90 ° = Other 2 angles
90 ° = a + b
90 ° = 28.072° + 61.93°
90 ° = 90 °
Result:
The other 2 angles of given right angles are 61.93° and 28.07°, if a triangle with side lengths 8, 15, and 17 is a right triangle by the converse of the Pythagorean Theorem.
The answer for the given above is letter "a, -6r2s4t3". This is obtained by dividing 18 by -3 and subtracting the exponent below with that from above of the same variable. For r, subtract 2 from 4 to get 2. For s, subtract 1 from 5 to get 4 and lastly for t, subtract 3 from 6 to get 3.
Answer:
53°
Step-by-step explanation:
It is given that the total measurement of the two angles combined would equate to 116°.
It is also given that m∠WXY is 10° more then m∠ZXY.
Set the system of equation:
m∠1 + m∠2 = 116°
m∠1 = m∠2 + 10°
First, plug in "m∠2 + 10" for m∠1 in the first equation:
m∠1 + m∠2 = 116°
(m∠2 + 10) + m∠2 = 116°
Simplify. Combine like terms:
2(m∠2) + 10 = 116
Next, isolate the <em>variable</em>, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 10 from both sides of the equation:
2(m∠2) + 10 (-10) = 116 (-10)
2(m∠2) = 116 - 10
2(m∠2) = 106
Next, divide 2 from both sides of the equation:
(2(m∠2))/2 = (106)/2
m∠2 = 106/2 = 53°
53° is your answer.
~
6 is in the tenths place.
Written Form: 0.6
