Step-by-step explanation:
We have,
The frequency of note A is 880 Hz and the frequency of note D is 1175 Hz. It is required to find the ratio of D to A.
It means
.
Using the values of frequency of D and A. So,

In decimal form,

In integer form,

Answer:
C)-2(9+32n)
Step-by-step explanation:
The given expresion is

We can rewrite this expression as:

We factor -2 to obtain:

Note that, we can use the distributive property to obtain:

Therefore the correct answer is C)-2(9+32n)
i think the answer is 8 dogs and 7 cats 15 in total
For this case we have the following quadratic equation:

By the time the projectile hits the ground we have the final height equal to zero:

Therefore, we have a second-order polynomial that we must solve:
Using resolver we have:

Rewriting:

Doing the calculations we have two roots:

We discard the negative root because we are looking for time which is greater than zero.
Answer:
the projectile will hit the ground after:
C. 5.3 seconds
2 X 10 3^ .............................