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3 years ago

15

jose rodriguez's checking account had a starting balance of 1,234.56. he wrote a check for 115.12 for plumbing supplies and chec

k for 225.00 for a loan payment. Yesterday he deposited 96.75 in his checking account. what jose's current balance?

1 answer:

Nadya [2.5K]3 years ago

5 0

Jose's current balance is 991.12
Hopes this helps.

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Can someone please help meeeee :((<br>what's the rule?

Elena L [17]

I think the rule has something to do with adding. I noticed that when the input was at 0 the output was 20, When the input was 15 the output was 5, when the input was 8 the output was 12, and so on. I think the rule is, no matter what number is in the input or the output, it must equal 20.
Hope This Helps!

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3 years ago

What are the 2 shorter sides of a right triangle called

o-na [289]

A right triangle has two shorter sides, or legs, and the longest side, opposite the right angle, which is always called the hypotenuse. ... The other leg in the right triangle is then called the adjacent side.

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4 0

2 years ago

Read 2 more answers

Two numbers are said to be 'relatively prime' if their greatest common factor is 1. How many integers greater than 10 and less t

mars1129 [50]

Answer:

d. 9 integers

Step-by-step explanation:

Given that two numbers are said to be 'relatively prime' if their greatest common factor is 1.

We are to find relatively prime with 28 which are greater than 10 and less than 30

We have 11,12,13...29 satisfying the criteria greater than 10 and less than 30

To be relatively prime with 28, common factors should be only 1.

28 = 2x2x 7. Hence the numbers which do not have factors as 2 or 7 will be relatively prime. Remove all the even numbers from the list.

We have 11,13,15....29.

Of these 21 is the multiple of 7 so remove that.

Thus we have now 11,13,15,17,19,23,25,27,29

9 integers

d. 9 integers

3 0

3 years ago

Francis works at Carlos Bakery and is making cookie trays. She has 48 chocolate chip cookies, 64 rainbow cookies, and 120 oatmea

amm1812

The number of cookies and trays are illustrations of greatest common factors.

The number of trays is 8
6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

The given parameters are:

$\mathbf{Chocolate\ chip=48}$

$\mathbf{Rainbow=64}$

$\mathbf{Oatmeal=120}$

<u>(a) The number of trays</u>

To do this, we simply calculate the greatest common factor of 48, 64 and 120

Factorize the numbers, as follows:

$\mathbf{48 = 2 \times 2 \times 2 \times 2 \times 3}$

$\mathbf{64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2}$

$\mathbf{120 = 2 \times 2 \times 2 \times 3 \times 5}$

So, the GCF is:

$\mathbf{GCF= 2 \times 2 \times 2}$

$\mathbf{GCF= 8}$

Hence, the number of tray is 8

<u>(b) The number of each type of cookie</u>

We have

$\mathbf{Chocolate\ chip=48}$

$\mathbf{Rainbow=64}$

$\mathbf{Oatmeal=120}$

Divide each cookie by the number of trays

So, we have:

$\mathbf{Chocolate\ chip = \frac{48}{8} = 6}$

$\mathbf{Rainbow = \frac{64}{8} = 8}$

$\mathbf{Oatmeal = \frac{150}{8} = 15}$

Hence, 6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

Read more about greatest common factors at:

brainly.com/question/11221202

4 0

2 years ago

Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0

Arada [10]

Answer:

$b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$

Step-by-step explanation:

The given matrix addition is

$B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

We need to find the elements of matrix B.

Let $B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}$

Substitute the value of matrix.

$\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

After addition of two matrix we get

$\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

On equating both sides.

$b_{11}+15=1\Rightarrow b_{11}=-14$

$b_{12}-7=2\Rightarrow b_{12}=9$

$b_{13}+4=12\Rightarrow b_{13}=8$

$b_{21}+0=4\Rightarrow b_{21}=4$

$b_{22}+1=0\Rightarrow b_{22}=-1$

$b_{23}+2=2\Rightarrow b_{23}=0$

Therefore, the elements of matrix B are $b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$ .

3 0

3 years ago