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Nimfa-mama [501]
3 years ago
15

Tomas collects miniature cars. He bought a display case at a cost of $5.95. He also bought 3 miniature cars. If his total cost w

as $11.05, how much did each car cost?

Mathematics
2 answers:
kiruha [24]3 years ago
6 0
The answer should be D
ICE Princess25 [194]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
If you never pulled your money out of your account from the company in Question #4 and let it grow to age 60, how much money wou
Mariulka [41]

Answer:

1

Step-by-step explanation:

8 0
2 years ago
Write and solve a system of equations that represents each situation.
kotegsom [21]
(7+x)+x=15
I did trial and error to get x=4.
4 0
3 years ago
What is the factorise 3m-6
cupoosta [38]

The answer is:      "  3(m − 2)  "  .

__________________________________

  →  The "factorized version" of the binomial expression, " 3m − 6 " ,  is:

__________________________________

                →   "  3(m − 2) " .

__________________________________

Explanation:

To solve:

__________________________________

<u>Note</u>:  We are given the expression:  " 3m − 6 " ;

and we are asked to "factorize" this expression.

Note that this expression is a "binomial expression" — which means there are two (2) terms — in this case:   "3m" and "6" .

Since only one (1) of these 2 (two) terms has a variable, and the remaining terms is a "constant" (non-zero integer), write these 2 (two) terms as:

 1)  the coefficient of the variable given in the term shown with a "coefficient" :

       →   that is:  "3"  ;  and:

 2)  the other term:  "6" .

→  With the numbers:  "3 and 6" , we can factor out a "3" ;  

          →  {since:  " 6 ÷ 3 = 2 "} ;

 →   So;  given:  

               " 3m − 6 " ;  

 →   We can "factor out" a "3" ; as follows:

           →   Take the first term:  " 3m " :

                    " 3m  =  3 * m " ;

__________________________________

           →   Take the second term:  "  6 " :

                    "  6 = 3 * (what value?) ;

                 → divide each of this equation by "3" ;

    to isolate the "missing value" on one side of the equation; & to solve for the "missing value" ; as follows:

        →           "  6 / 3 = [ 3 * (what value?) ] / 3  ;

                    →  to get:  " 2  =  "(the missing value)"  ;

    →   So;    "  6 = 3 * (what value?) ;

           →     " 6 = 3 * 2 " .  

           →   Take the second term:  "  6 " :

           →     " 6 = 3 * 2 " .

__________________________________

So:    " 3m − 6 "  =  (3 * m) − (3 * 2) " .  

Factor out a "3" ;  as follows:

__________________________________

    →  " 3m − 6 "  =  (3 * m) − (3 * 2) " ;

                           =   " 3(m − 2)  "

__________________________________

Let us check our answer:

__________________________________

Note the "distributive property of multiplication"  :

__________________________________

        a(b + c) = ab +  ac ;  

        a(b − c) = ab −  ac ;

__________________________________

So:  Take our answer:  " 3(m − 2) " .

__________________________________

" 3(m − 2)  = ?  (3*m)  −  (3*2)  " ??  ;

__________________________________

Let us substitute "4" for "m" ;  in both sides of the equation;

              →  to see if the equation holds true;  i.e. to see if both sides of the equation are equal when:  " m = 4 " ;

__________________________________

 We have:

__________________________________

     →  " 3(m − 2)  = ?  (3*m)  −  (3*2)  " ??  ;

First let us rewrite this equation;  substitute "4" for "m" ; as follows:

     →   " 3(4 − 2)  = ?  (3*4)  −  (3*2)  " ??  ;

__________________________________

And calculate;  to see if each side of the equation is equal ; i.e. to see if the equation holds true; as follows:

     →   " 3(2)  = ?  (12)  −  (6)  " ??  ;

     →   "  6  = ?  (6)  " ??  ;

     →   "  6 = 6 " !  Yes!  The equation holds true!

__________________________________

Hope this answer was helpful!

Best wishes!

__________________________________

8 0
3 years ago
150 adults complete a survey 80 are women write the ratio men:women in its simplest form
noname [10]
7:8 is the ratio of men:women
6 0
3 years ago
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