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postnew [5]
3 years ago
7

Please check my answer!

Mathematics
1 answer:
umka21 [38]3 years ago
3 0

A ) P=6n+18 where N is the number of triangles. There's always two '9's and the 6 is based on how many triangles there are.

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(3+5)x7-[10+(45-15)\5]
Gelneren [198K]
Use\ PEMDAS\\\\(3+5)\times7-[10+\frac{(45-15)}{5}]=(8)\times7-(10+\frac{30}{5})\\\\=56-(10+6)=56-16=\boxed{\boxed{40}}
7 0
3 years ago
On a piece of paper, sketch △ABC with m∠A=30° , m∠B=60° , and m∠C=90° . Which statements about the triangle are true? Select eac
gladu [14]

Answer:

Step-by-step explanation:i dont know duuu

6 0
3 years ago
WHY AM I DOING SCHOOL AT 2AM -.-
irakobra [83]
The points go on the little lines. It’s hard to point out
5 0
2 years ago
Which relation is a function?
xz_007 [3.2K]

Answer:

I see this

"Which relation is a function?

A {(-3,4),(-3,8),(6,8)}

B {(6,4),(-3,8),(6,8)}

C {(-3,4),(3,-8),(3,8)}

D {(-3,4),(3,5),(-3,8)}"

So the answer is none of these.

Please make sure you have the correct problem.

Step-by-step explanation:

A set of points is a function if you have all your x's are different.  That is, all the x's must be distinct. There can be no value of x that appears more than once.

If you look at choice A, this is not a function because the first two points share the same x, which is -3.

Choice B is not a function because the first and last point share the same x, which is 6.

Choice C is not a function because the last two points share the same x, which is 3.

Choice D is not a function because the first and last choice share the same x, which is -3.

None of your choices show a function.

If you don't have that choice you might want to verify you written the problem correctly.

This is what I see:

"Which relation is a function?

A {(-3,4),(-3,8),(6,8)}

B {(6,4),(-3,8),(6,8)}

C {(-3,4),(3,-8),(3,8)}

D {(-3,4),(3,5),(-3,8)}"

7 0
3 years ago
2 times the square root of 27 minus the square root of 48
lyudmila [28]
2 \sqrt{27}- \sqrt{48}=2 \sqrt{9*3}- \sqrt{16*3} =2*3 \sqrt{3}- 4 \sqrt{3}=6 \sqrt{3}-4 \sqrt{3} = \\ =2 \sqrt{3}
5 0
3 years ago
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