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kakasveta [241]
4 years ago
7

1A=bh

Mathematics
1 answer:
seropon [69]4 years ago
6 0

Answer:

120 yd2

Step-by-step explanation:

I assume you are solving for area.

The formula for a paralellogram (what it appears to be) is base times height.

The base in this equation is 10, and the height is 12. Multiplying this you get 120 yards squared.

For perimeter, you use pythagorean theorem to get the diagonal. 2\sqrt{61} . Then multiply 10 and 2\sqrt{61} by two, and then add them. 20+4\sqrt{61}.

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C. The range represents the number of users each month for 36 months.
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3 years ago
A cylinder has a 12-inch diameter and is 15 inches tall. It is filled to the top with water. A 6-inch-diameter ball is placed wi
Tems11 [23]

The volume of the cylinder is the space occupied by the cylinder. The volume of the water in the cylinder is 1583.36266 in³.

<h3>What is the volume of a cylinder?</h3>

The volume of the cylinder is the space occupied by the cylinder. It is calculated with the help of the formula,

\text{Volume of the cyllinder}= \pi r^2h

As it is given that the diameter of the cylinder is 12 inches while the height of the cylinder is 15 inches, also, it has a ball of the diameter of 6 inches placed inside the cylinder, therefore, the volume of the water that is inside the cylinder is the difference in the volume of the cylinder and the volume of the spherical ball.

\text{Volume of the cyllinder}= \pi r^2h = \dfrac{\pi}{4}d^2 h

Substitute the values,

\begin{aligned}\text{Volume of the cyllinder}&= \dfrac{\pi}{4}d^2 h\\& = \dfrac{\pi}{4} \times (12^2) \times 15\\ &=1696.46\rm\ in^3\end{aligned}

Now, the volume of the ball is equal to the volume of the sphere therefore, the volume of the ball can be written as,

\text{Volume of the sphere} = \dfrac{4}{3}\pi r^3

                                  = \dfrac{4}{3}\pi r^3\\\\=  \dfrac{4}{3}\times \pi \times (3^3)\\\\= 113.097\rm\ in^3

Further, the volume of the water that is inside the cylinder can be written as,

The volume of water =  Volume of the cylinder - Volume of the sphere

                                   = 1696.46 - 113.097

                                   = 1583.36266 in³

Hence, the volume of the water in the cylinder is 1583.36266 in³.

Learn more about Volume of the Cylinder:

brainly.com/question/1780981

5 0
2 years ago
What are the steps for long division?
diamong [38]
This is what I learned:

D = Divide
M = Multiply
S = Subtract
B = Bring down
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D= Dad
M= Mom
S= Sister
B= Brother
C= Cousin

Hope this helped you! :)
8 0
4 years ago
A cylinder has a height of 18 millimeters and a radius of 18 millimeters. What is its volume? Use ​ ≈ 3.14 and round your answer
solong [7]

Answer:

Volume = 18312.48

Step-by-step explanation:

Given

Height (h) = 18mm

Radius (r) = 18mm

Required

Determine the volume

The volume of a cylinder is calculated as thus:

Volume = \pi r^2h

Substitute values for r and h

Volume = 3.14 * 18^2 * 18

Volume = 18312.48

<em>Hence, the volume of the cylinder is 18312.48mm³</em>

8 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
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