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trasher [3.6K]
3 years ago
8

Please help with this question and show work

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0
The diagonals of a parallelogram bisect each other so
4x - 7 = x + 2 and
5y - 8 = 3y

4x - 7 = x + 2 so 3x = 9 and x = 3

5y - 8 = 3y so 2y = 8 and y = 4
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Write an inequality that represents this situation
Studentka2010 [4]
What is the situation?
7 0
3 years ago
What is the answer a, b, c, or d
podryga [215]

Answer: Choice B

(-2, 5)

==================================================

Explanation:

The original system is

\begin{cases}-4x+3y = 23\\ x-y = -7\end{cases}

Multiply both sides of the second equation by 3. Doing so leads to this updated system of equations

\begin{cases}-4x+3y = 23\\ 3x-3y = -21\end{cases}

Now add straight down

The x terms add to -4x+3x = -1x = -x

The y terms add to 3y+(-3y) = 0y = 0

The terms on the right hand sides add to 23+(-21) = 2

We end up with the equation  -x = 2 which solves to x = -2

Now use this to find y. You can pick any equation with x,y in it

----------------

-4x+3y = 23

-4(-2)+3y = 23

8+3y = 23

3y = 23-8

3y = 15

y = 15/3

y = 5

Or

x-y = -7

-2-y = -7

-y = -7+2

y = -5

y = 5

Either way, we get the same y value.

So that's why the solution is (x,y) = (-2, 5)

6 0
2 years ago
What is the angle e in the triangle below? (Hint: Use an inverse trigonometric
yuradex [85]

Answer:

A

Step-by-step explanation:

sin θ=3/8

θ=sin ^{-1}(3/8)

≈22.02 °

5 0
2 years ago
Read 2 more answers
< Previous
Free_Kalibri [48]

Answer:

T(2, -7) = (4, -10)

Step-by-step explanation:

T(x, y) = (x + 2, y - 3)

T(2, -7) = (2 + 2, -7 - 3)

T(2, -7) = (4, -10)

3 0
2 years ago
Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
1 year ago
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