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3 years ago

Find measures of each exterior angle of a regular polygon with 16 sides

Mathematics

2 answers:

Maksim231197 [3]3 years ago

3 0

The measure of each exterior angle = the measure of each central angle.
each angle = 360 / 16 = 22.5

qwelly [4]3 years ago

3 0

Answer: 22.5°

Step-by-step explanation: In this problem, we are asked to find the measure of each exterior angle of a regular polygon that has 16 sides.

The formula for finding the measure of each exterior angle of a regular polygon is similar to the formula for finding the measure of each interior angle.

We take the sum of the measures of the exterior angles which is always 360° divided by the number of sides in the polygon which is n. So the formula for finding the measure of each exterior angle of a regular polygon is 360/n.

In this problem, since the polygon has 16 sides, we simply plug a 16 in for n in our formula and we have 360 divided by 16 which is 22.5.

So the measure of each exterior angle of a regular polygon that has 16 sides is 22.5°.

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2 years ago

Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

kondaur [170]

Answer:

The solution of $\bold{\frac{M^{2}}{P^{2}}}$ for M = 10, N = -5P and P = -2 is 25

Solution:

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of $\frac{M^{2}}{P^{2}}$ ,

By substituting the values of M and N, we get

$\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$

Expanding $\bold{10^{2}}$ :

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

$10^{2} = 10 \times 10 = 100$

Similarly expanding $\bold{(-2)^{2}}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

$(-2)^{2} = -2 \times -2 = 4$

So the equation $\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$ becomes,

$\frac{M^{2}}{P^{2}} = \frac{100}{4}$

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Hence the solution of $\bold{\frac{M^{2}}{P^{2}}}$ when M = 10 and P = -2 is 25

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3 years ago

Find the greatest common factor of 5n and 8n^2

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Answer:

Step-by-step explanation:

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3 years ago

Two litters of a particular rodent species have been born; first with two brownhaired and one gray-haired (litter 1) and the oth

maks197457 [2]

Answer:

The probability that the animal chosen is brown-haired is 0.6333.

Step-by-step explanation:

Denote the events as follows:

A : a brown-haired rodent

B : Litter 1

The information provided is:

$P (A|B) =\frac{2}{3}\\\\P(A|B^{c})=\frac{3}{5}$

The probability of selecting any of the two litters is equal, i.e.

$P(B)=P(B^{c})=\frac{1}{2}$

According to the law of total probability:

$P(X)=P(X|Y_{1})P(Y_{1})+P(X|Y_{2})P(Y_{2})+...+P(X|Y_{n})P(Y_{n})$

Compute the total probability of event A as follows:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

$=[\frac{2}{3}\times\frac{1}{2}]+[\frac{3}{5}\times\frac{1}{2}]\\\\=\frac{1}{3}+\frac{3}{10}\\\\=\frac{10+9}{30}\\\\=\frac{19}{30}\\\\=0.6333$

Thus, the probability that the animal chosen is brown-haired is 0.6333.

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3 years ago

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andrey2020 [161]

Answer:No value of x

Step-by-step explanation:

Given

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Let $2^x=y$

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or $2^x=-4$

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because minimum value of $^x=1$

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