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BigorU [14]
3 years ago
10

Carrie is looking for a job cutting hair. One option is self-employment at The Belmont Salon, where she would pay $438 per month

to rent a station and keep all her earnings. Another option is to work at a franchise, where she just have to pay $2 for every haircut. if she performed a certain number of haircuts every month, the amount paid to either salon would be the same. how much would Carrie pay? how many haircuts would that be? ( Can you also show the steps please?)
Mathematics
1 answer:
Digiron [165]3 years ago
6 0

Answer:

She would have to do 219 haircuts in a month for the costs to be the same, which would be $428.

Step-by-step explanation:

To find this we take the costs of the first place.

$438

Next we can look at the costs of the second place using x as the number of haircuts she'd do.

2x

Now we can set the two equal to each other to find the number of cuts.

438 = 2x

219 = x

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Alica has 32 stickers .this is 4 times as many as benita has .how many sticker does benita have?
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Work out 32 times by 4
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3 years ago
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WHAT IS THE PRIME FACTORIZATION FOR ONE BILLION
Ivan
1 billion is=1,000,000,000
count the zeros since it has only 10's as the factors
9 zeros
the 10=2 times 5
so there are 10 2's and 10 5's so the prime factorization is
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3 0
3 years ago
6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP
adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

       = 12.703

y = 12.70 km

\frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0
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i think it's 20 but i'm not that sure

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