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amm1812
3 years ago
14

A student has some​ $1 and​ $5 bills in his wallet. He has a total of 15 bills that are worth ​$39. How many of each type of bil

l does he​ have?
Mathematics
1 answer:
Bingel [31]3 years ago
6 0
He has nine $1 bills and six $5 bills.
You might be interested in
What is the solution to 3/(2x+1) = 9/3x?
Scorpion4ik [409]

Answer:

Solution x = - 1

Step-by-step explanation:

3 / (2x+1) = 9 / 3x

Cross multiply

3(3x) = 9(2x + 1)

Distributive property

9x = 18x + 9

Subtract 18x from both sides

-9x = 9

Divide both sides by -9

x = -1

7 0
3 years ago
Return to the credit card scenario of Exercise 12 (Section 2.2), and let C be the event that the selected student has an America
Nadya [2.5K]

Answer:

A. P = 0.73

B. P(A∩B∩C') = 0.22

C. P(B/A) = 0.5

   P(A/B) = 0.75

D. P(A∩B/C) = 0.4

E. P(A∪B/C) = 0.85

Step-by-step explanation:

Let's call A the event that a student has a Visa card, B the event that a student has a MasterCard and C the event that a student has a American Express card. Additionally, let's call A' the event that a student hasn't a Visa card, B' the event that a student hasn't a MasterCard and C the event that a student hasn't a American Express card.

Then, with the given probabilities we can find the following probabilities:

P(A∩B∩C') = P(A∩B) - P(A∩B∩C) = 0.3 - 0.08 = 0.22

Where P(A∩B∩C') is the probability that a student has a Visa card and a Master Card but doesn't have a American Express, P(A∩B) is the probability that a student has a has a Visa card and a MasterCard and P(A∩B∩C) is the probability that a student has a Visa card, a MasterCard and a American Express card. At the same way, we can find:

P(A∩C∩B') = P(A∩C) - P(A∩B∩C) = 0.15 - 0.08 = 0.07

P(B∩C∩A') = P(B∩C) - P(A∩B∩C) = 0.1 - 0.08 = 0.02

P(A∩B'∩C') = P(A) - P(A∩B∩C') - P(A∩C∩B') - P(A∩B∩C)

                   = 0.6 - 0.22 - 0.07 - 0.08 = 0.23

P(B∩A'∩C') = P(B) - P(A∩B∩C') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.4 - 0.22 - 0.02 - 0.08 = 0.08

P(C∩A'∩A') = P(C) - P(A∩C∩B') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.2 - 0.07 - 0.02 - 0.08 = 0.03

A. the probability that the selected student has at least one of the three types of cards is calculated as:

P = P(A∩B∩C) + P(A∩B∩C') + P(A∩C∩B') + P(B∩C∩A') + P(A∩B'∩C') +              

     P(B∩A'∩C') + P(C∩A'∩A')

P = 0.08 + 0.22 + 0.07 + 0.02 + 0.23 + 0.08 + 0.03 = 0.73

B. The probability that the selected student has both a Visa card and a MasterCard but not an American Express card can be written as P(A∩B∩C') and it is equal to 0.22

C. P(B/A) is the probability that a student has a MasterCard given that he has a Visa Card. it is calculated as:

P(B/A) = P(A∩B)/P(A)

So, replacing values, we get:

P(B/A) = 0.3/0.6 = 0.5

At the same way, P(A/B) is the probability that a  student has a Visa Card given that he has a MasterCard. it is calculated as:

P(A/B) = P(A∩B)/P(B) = 0.3/0.4 = 0.75

D. If a selected student has an American Express card, the probability that she or he also has both a Visa card and a MasterCard is  written as P(A∩B/C), so it is calculated as:

P(A∩B/C) = P(A∩B∩C)/P(C) = 0.08/0.2 = 0.4

E. If a the selected student has an American Express card, the probability that she or he has at least one of the other two types of cards is written as P(A∪B/C) and it is calculated as:

P(A∪B/C) = P(A∪B∩C)/P(C)

Where P(A∪B∩C) = P(A∩B∩C)+P(B∩C∩A')+P(A∩C∩B')

So, P(A∪B∩C) = 0.08 + 0.07 + 0.02 = 0.17

Finally, P(A∪B/C) is:

P(A∪B/C) = 0.17/0.2 =0.85

4 0
3 years ago
Below are 36 sorted ages of an acting award winner. Find Upper P70 using the method presented in the textbook.
Leona [35]
The upper 70th percentile is the number below which 70% of the data lie.

The 70th percentile position is given by:

P_{70}= \frac{70N}{100} = \frac{70(36)}{100} =25.2

Thus, the 70th percentile position is approximately the 25th data item (after the data has been arranged in acsending order).

Given the following data:
<span>16 24 25 26 27 29 36 39 39 39 40 44 45 47 47 48 50 51 51 53 53 54 57 58
58 60 65 66 67 69 69 71 72 74 74 74

The 25th data in the data set is 58.

Therefore, the upper P70 is 58.
</span>
6 0
3 years ago
Read 2 more answers
What is the length of AC?<br><br><br> 3 ft<br><br> 4 ft<br><br> 9 ft<br><br> 18 ft
iragen [17]

Answer: The length of AC is 18 ft.

Step-by-step explanation:

By the given diagram,

AM = MB and CN = NB

M and N are the mid points of the sides AB and CB respectively,

Thus, by the mid point theorem,

MN ║ AC,

By the alternative interior angle theorem,

∠BMN ≅ ∠BAC

∠BNM ≅ ∠BCA

Thus, by AA similarity postulate,

ΔBMN ≅ ΔBAC

By the property of similar triangles,

\frac{BM}{BA}=\frac{MN}{AC}

\frac{BM}{BM+MA}=\frac{MN}{AC}

\frac{4}{4+4}=\frac{9}{AC}

\frac{4}{8}=\frac{9}{AC}

4AC=72\implies AC = 18\text{ ft}

Thus, The length of AC is 18 ft.

5 0
3 years ago
Read 2 more answers
Which of the following is equivalent to (Cd) to the fifth power
Rina8888 [55]

Answer:

The 3rd option is correct.

Step-by-step explanation:

This is because of an exponent rule that goes:

(xy)^z = x^z(y^z)

The whole thing gets raised to the power. Therefore only the 3rd one works (ps. if you can mark as brainliest that would be amazing, but if not that's fine)

5 0
2 years ago
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