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melamori03 [73]
3 years ago
12

The function h(x) = 12x8 + 49 is an even function. Which transformation of h(x) would result in a function that is neither even

nor odd? reflection over the x-axis vertical stretch by a factor of 7 translation 8 units to the right horizontal compression by a factor ofOne-half
Mathematics
1 answer:
Irina-Kira [14]3 years ago
3 0

Answer:  translation 8 units to the right

Step-by-step explanation:

An even function is a function such that:

h(x) = h(-x)

and the function is odd if:

h(-x) = -h(x)

Now, let's talk about transformations:

A) Reflection over the x-axis:

When we have a point (x,y) and we do a reflection over the x-axis, the reflected point will be:

(x, -y).

Then for the case of a function:

y = h(x).

then the reflection will be:

g(x) = - y = -h(x).

And if h(x) is even, -h(x) is also even, so this is not the correct option.

B) Vertical stretch by a factor of 7.

This is written as:

g(x) = 7*h(x).

then:

g(x) = 7*h(x)

g(-x) = 7*h(-x) = 7*h(x) = g(x)

the transformation is even.

C) Translation of 8 units to the right.

We can write this as:

g(x) = h(x - 8).

Then:

g(-x) = h(-x -8) = h(x + 8)

Then g(-x) is not equal to g(x)

and also g(-x) ≠ -g(x)

So in this case the transformation is neither odd or even.

C)  horizontal compression by a factor of One-half.

This transformation is written as:

g(x) = h( (1/2)*x)

And, similar as the case of the vertical compression, in this case the transformation is also even.

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Math
lozanna [386]

Answer:

1. x=6

2. C <-26

3. p<6

4. -5x-44

Step-by-step explanation:

1. 2x = 3(x-2) - 3(x-6)

Distribute

2x= 3x-6 -3x+18

Combine like terms

2x =12

Divide by 2

2x/2 =12/2

x=6


2. C+6<-20

   Subtract 6 from each side

C+6-6 < -20-6

C <-26


3. -5p > -30  

Divide by -5.  Remember to flip the inequality when dividing by a negative

-5p/-5 < -30/-5

p<6


4. -4 - 5(X+8)

Distribute

-4 -5x-40

Combine like terms

-5x-44

6 0
4 years ago
I need these 4 I really don't understand this​
Fed [463]

Answer:

6:

{x}^{2}  - 2x - 3 \\  = (x - 3)(x + 1) \\ when \: y = 2 \\ x = 1 \\ vertex \: is \: (1, \: 2)

7:

{x}^{2}  =  - 625 \\ x =  \sqrt{ - 625}  \\ x =  \sqrt{625}  \times  \sqrt{ - 1}  \\ x = 25 \times  \sqrt{ {i}^{2} }  \\ x = 25 \times i \\ x  = 25i

8 0
3 years ago
5x^2+20=30 please show all work
mezya [45]
5x^2+20=30\\&#10;5x^2=10\\&#10;x^2=2\\&#10;x=-\sqrt2 \vee x=\sqrt2
8 0
4 years ago
Find the measures of the angles and arcs identified below​
harkovskaia [24]

Answer:

∠a = 42.5°

∠b = 87°

∠c = 174°

∠d = 90°

∠f = 131°

Step-by-step explanation:

∠a = 85°/2 = 42.5°

∠b = 360° -110° - 76° = 174°/2 = 87°

∠c = 360° -110° - 76° = 174°

∠d = 90°

∠f = 360° - 101° - (64° x 2) = 131°

4 0
3 years ago
Rickey has been commissioned to paint a mural that is allowed to have an area of 50 square meters. To make the rectangle shape o
Leno4ka [110]

Answer:

12.808 meter is the length should Rickey use for the mural.

Step-by-step explanation:

Area of the mural = A = 50 m^2

Length of the mural = l

Width of the mural = w

l = 5 + 2w

Area of the rectangle = l × w

A=(5+2w)\times w

50 m^2=5w+2w^2

2w^2+5w-50=0

Solving above equation with the help of Completing squares method:

(\sqrt{2}w)^2+2\times \sqrt{2}w\times \frac{5}{2\sqrt{2}}+(\frac{5}{2\sqrt{2}})^2-50=(\frac{5}{2\sqrt{2}})^2

(a+b)^2=a^2+b^2+2ab

(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=(\frac{5}{2\sqrt{2}})^2+50

(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=\frac{25}{8}+50

(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=\frac{425}{8}

(\sqrt{2}w+\frac{5}{2\sqrt{2}})=\pm\sqrt{\frac{425}{8}}

w = 3.904 m (accept)

w = -6.404 m (reject)

l = (5 + 2w)m = 5 + 2 × (3.904) m= 12.808 m

12.808 meter is the length should Rickey use for the mural.

3 0
3 years ago
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