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3 years ago

What is the name of the property that is shown -7+0=-7

Mathematics

2 answers:

masha68 [24]3 years ago

5 0

Answer: identity property

Step-by-step explanation: The identity property holds true for addition. The statement -7 + 0 = -7 represents the identity property of addition. The identity property of addition says that when we add zero to any number, the sum is equal to the original number.

In general terms,

we can write the identity property of addition as a + 0 = a where a is a variable that represents any number.

kotykmax [81]3 years ago

4 0

Answer:

Step-by-step explanation:

-7 + 0 = -7

the addition property of zero....it states that any number added to zero, the sum equals that number.

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3 years ago

A store owner uses a selling price of 125% of the cost of an item. If a pair of jeans has a sales price of $52.50, what cost doe

IgorC [24]

Answer:

The cost store owner pay for the pair of jeans is $42.

Step-by-step explanation:

Given:

A store owner uses a selling price of 125% of the cost of an item.

If a pair of jeans has a sales price of $52.50.

Now, to find the cost price of the store owner pay for the pair of jeans.

Let the cost price of jeans be $x.$

Sell price of jeans = $\$52.50.$

Now, to get the cost price of store owner pay for the pair of jeans:

As given the store owner uses a selling price of 125% of the cost of an item.

According to question:

$125\%\ of\ x=52.50$

$\frac{125}{100} \times x=52.50$

$1.25x=52.50$

Dividing both sides by 1.25 we get:

$x=42.$

The cost price of jeans = $42.

Therefore, the cost store owner pay for the pair of jeans is $42.

6 0

3 years ago

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

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2 years ago

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andre [41]

Answer:

4 the answer is 4

Step by step explanatin:

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2 years ago