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Vlad [161]
3 years ago
11

A sheet of plywood was made by gluing 7 sheets of wood together.

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0
We can use the equation y=2(0.0625)+5(0.125), y being the thickness of the plywood.
I got 5(0.125) because two sheets of the 7 were already used, meaning there are 5 sheets of plywood left over.
y=0.125+0.625
y=0.75
Therefore, the plywood is 0.75 inches thick.
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In which number does the 6 have a value that is one tenth the value of the 6 in 34, 761
bogdanovich [222]
I believe the answer you're looking for is 6, as the value of the 6 in 34,761 is 60. Hope this helps!
4 0
3 years ago
Find an equation for the line that passes through the given point and satisfies the given conditions. 11) 11) p = ( 9 , 2 ); per
geniusboy [140]

You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)

Translating the line up 2 and right 9, so it goes through the given point, we get ...

... (x -9) +(y -2) = 0

or

... x + y = 11

5 0
3 years ago
Pls help… grade 6/ primary 6 work. thanks!
Yuri [45]

Answer:

320

Step-by-step explanation:

go backwards, 75 + 45 = 120

120 * 5/3 = 200

200+40 = 240

240 *4/3 = 320

3 0
2 years ago
Abc~def what sequence of transformation will move ABC onto def ​
DENIUS [597]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (
kvasek [131]

Answer:

a) P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

b) False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

c) False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

Step-by-step explanation:

For this case we have the following probabilities given:

P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9

Part a

We want to calculate the following probability: P(A \cap B)

And we can use the total probability rule given by:

P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

Part b

False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

Part c

False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

4 0
3 years ago
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