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lana66690 [7]
4 years ago
5

A busy chipmunk runs back and forth along a straight line of acorns that has been set out between its burrow and a nearby tree.

At some instant, it moves with a velocity of −1.29 m/s−1.29 m/s . Then, 2.91 s2.91 s later, it moves with a velocity of 1.77 m/s1.77 m/s . What is the chipmunk's average acceleration during the 2.91 s2.91 s time interval?
Physics
1 answer:
timofeeve [1]4 years ago
3 0

Answer:

1.05 ms⁻²

Explanation:

Acceleration = change in velocity / Time

Change in velocity = Final velocity - initial velocity

= 1.77 - (-1.29)

= 1.77 + 1.29

= 3.06 m/s

Time = 2.91

Acceleration = 3.06 / 2.91

= 1.05 ms⁻² .

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A4.0 kg object is moving with speed 2.0 m/s. A 1.0 kg object is moving with speed 4.0 m/s. Both objects encounter the same const
Evgesh-ka [11]

Answer:

Both objects travel the same distance.

(c) is correct option

Explanation:

Given that,

Mass of first object = 4.0 kg

Speed of first object = 2.0 m/s

Mass of second object = 1.0 kg

Speed of second object = 4.0 m/s

We need to calculate the stopping distance

For first particle

Using equation of motion

v^2=u^2+2as

Where, v = final velocity

u = initial velocity

s = distance

Put the value in the equation

0= u^2-2as_{1}

s_{1}=\dfrac{u^2}{2a}....(I)

Using newton law

a=\dfrac{F}{m}

Now, put the value of a in equation (I)

s_{1}=\dfrac{8}{F}

Now, For second object

Using equation of motion

v^2=u^2+2as

Put the value in the equation

0= u^2-2as_{2}

s_{2}=\dfrac{u^2}{2a}....(I)

Using newton law

F = ma

a=\dfrac{F}{m}

Now, put the value of a in equation (I)

s_{2}=\dfrac{8}{F}

Hence, Both objects travel the same distance.

6 0
3 years ago
What types of changes effect the sun’s energy output?
Greeley [361]

Answer:

the answer is A Cycles of solar flares and prominences heat and cool the layers below the sun’s surface

Explanation:

i took the quiz

3 0
3 years ago
PLEASE GUYS I REALLY NEED HELP ASAP. THIS IS SO IMPORTANT, I AM EVEN WILLING TO PAY FOR REAL.
malfutka [58]
 <span>The bending of light rays by sun is twice in Einstein's theory as in Newton's theory of gravitation. Einstein's theory was verified by Eddington during the solar eclipse in 1919 

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3 0
3 years ago
Neurons are most associated with<br> A. senses<br> B. eyesight<br> C. chevrolet
andriy [413]

Answer:

eyesight i think

Explanation:

i hope this helps you

3 0
2 years ago
A block of gelatin is 120mm by 120mm by 40mm whrn unstressed. A force of 49N is applied tangentially to the upper surface causin
Inessa05 [86]

Answer:

The shearing stress is 10208.3333 Pa

The shearing strain is 0.25

The shear modulus is 40833.3332 Pa

Explanation:

Given:

Block of gelatin of 120 mm x 120 mm by 40 mm

F = force = 49 N

Displacement = 10 mm

Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain​, SS = ?

The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:

A = 40*120 = 4800 mm² = 0.0048 m²

The shearing stress:

Ss=\frac{F}{A} =\frac{49}{0.0048} =10208.3333Pa

The shearing strain is defined as the tangent of the displacement that the block over its length:

SS=tan\theta =\frac{Displacement}{L}  =\frac{10}{40} =0.25

Finally, the shear modulus is the division of the shearing stress over the shearing strain:

Sm=\frac{10208.3333}{0.25} =40833.3332Pa

6 0
4 years ago
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