All categories

3 years ago

CAN SOMEBODY PLZ HELP ME WITH THIS 60 PTS + BRAINLIEST !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics

2 answers:

EleoNora [17]3 years ago

5 0

Answer:

https://science.howstuffworks.com/electromagnet.htm

Explanation:

that will help you

maw [93]3 years ago

3 0

Is this what you were looking for?

Brain, Marshall, and Lance Looper. “Howstuffworks Electromagnets .” Science, HowStuffWorks, /elescience.howstuffworks.comctromagnet.htm.

You might be interested in

The speed of the fastest pitched baseball was 45 m/s, and the ball’s mass was 145 g. How fast would a 59 g ball have to travel t

dsp73

59 g ball will travel upto 110 m/s

A. 110 m/s

Explanation:

Given datas are as follows

Speed of the pitched baseball = 45 meters/second

Mass of the baseball = 145 gram

Mass of the assumed ball = 59 gram

Both the balls travelled in the same momentum

Formula to find the momentum of an object is,

Momentum (p) = Mass (m) × velocity (v) (unit is kilogram meter per second (kg-m/s))

Momentum = 145 × 45 kilogram meter per second

Momentum = 6525 kilogram meter per second

Now calculate the speed of a ball with mass 59 g to have the momentum of about 6525 kilogram meter per second

Speed = momentum ÷ mass (meters per second)

Speed = 6525 ÷ 59 (meters per second)

Speed = 110 meters per second

Therefore a 59 gram (g) ball have to travel at a speed of 110 meters per second to have the momentum of 6525 kilogram-meter per second.

7 0

3 years ago

In the physics lab, a cart with a mass of 1 kg is found to have an acceleration of 50 cm/s^2 when it is pulled by a string with

Vlad [161]

Answer:

a = 25 cm/s²

Explanation:

Given,

The mass of the cart, m = 1 Kg

The acceleration of the cart, a = 50 cm/s²

The string with clay hanging off the ramp exerts a force, F on the cart (neglecting the tension in the string)

F = m x a

= 1 Kg X 50 cm/s²

= 50 Kg cm/s²

Hence the force exerted by the clay hanging off the ramp on the cart, F = 50 Kg cm/s²

If the mass of the cart is doubled '2 Kg', the same magnitude of the force acts on the cart.

Therefore, from the equation,

F = m x a

50 Kg cm/s² = 2 Kg x a

a = 50 Kg cm/s² / 2 Kg

= 25 cm/s²

Hence, the acceleration of the cart is, a = 25 cm/s²

3 0

4 years ago

What type of system allows energy but not matter to enter and exit?

Nastasia [14]

Answer:

closed

Explanation:

A closed system allows energy (usually heat) to be exchanged but not matter.

Your welcome

5 0

3 years ago

6. According to Ohm's Law, current (I), voltage (V), and resistance (R)

SIZIF [17.4K]

Answer: C

Explanation: according to the law voltages = to current and resistance

7 0

3 years ago

A paintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm b

Artist 52 [7]

Answer:

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

Explanation:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = u m/s

Acceleration = 0 $m/s^2$

So $4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}$

Now at time 2t,

$S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm$

So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = 0 m/s

Acceleration = -g $m/s^2$

$4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}$

At time 2t,

$S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm$

So vertical distance traveled in time 2t = 16 cm to the bottom

6 0

3 years ago