Answer:
final temperature is 364.32 K
mass of air is 0.5423 kg
Explanation:
given data
pressure p1 = 380 kPa
volume v1 = 0.120 m³
temperature = 20°C = 20 + 273 = 293 K
pressure p2 = 3450 kPa
volume v2 = 5% increase
to find out
final temperature and the mass
solution
we consider here ideal gas
so equation is
p1v1 / t1 = p2v2/t2
put here all value and find t2
and v2 is = 0.120 ( 1 + 0.05) = 0.126 m³
so
t2 = p2v2/ p1v1 × t1
t2 = (450 × 0.126) / (380 × 0.120) × 293
t2 = 364.32 K
so final temperature is 364.32 K
and
mass = p2v2 / Rt2
here R gas constant is 0.287 kJ/kg.K
so
mass = (450 × 0.126) / (0.287 × 364.32 )
mass = 0.5423
so mass of air is 0.5423 kg
Answer:
1. friends getting you to study
2. leading you to make the right decision
3. giving you advice pushing you towards whats right
4. pressuring you to be a good person
5. telling you when in the wrong
Explanation:
all of these are ways of positive peer pressure
Answer:
The distance between first-order and second-order bright fringes is 12.66mm.
Explanation:
The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.
(1)
Where
is the distance between two adjacent maxima, L is the distance of the screen from the slits,
is the wavelength and d is the separation between the slits.
The values for this particular case are:



Notice that is necessary to express L and
in units of milimeters.
⇒ 
⇒ 
Finally, equation 1 can be used:
Hence, the distance between first-order and second-order bright fringes is 12.66mm.