1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tino4ka555 [31]
3 years ago
9

A force AB of length 100m and weight 600N has its centre of gravity 4.0 m from the end, and lies on horizontal ground calculate

the force required to begin to lift the end
Physics
1 answer:
Stells [14]3 years ago
8 0

Answer:

F = 24 N

Explanation:

In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end

Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity

           ∑ τ = 0

           F l -x W = 0

           F = \frac{x}{l} \  W

let's calculate

          F = \frac{4}{100}4/100 600

          F = 24 N

You might be interested in
1. A force acting on an object in the upward direction is 3 N. The force that would
DENIUS [597]

Answer:

See the explanation below

Explanation:

We must perform a sum of forces on the body, that sum of forces is equal to zero. That is, the body is in balance and does not move.

ΣF = 0

3 - 3 = 0

This force is negative and acts by pointing downwards.

4 0
3 years ago
Read 2 more answers
Trial 1: Get a textbook and put a sheet of paper on top of it. Fold the paper as needed to keep the paper from sticking over the
siniylev [52]

Answer:

1)  the two objects reach the floor at the same time.

2)the book reaches the floor much earlier than the foil

In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more

Explanation:

This interesting experiment has the following results

1) first case. Sheet on top of book

In this case the two objects reach the floor at the same time.

This shows that the acceleration in the two objects is the same and we call it the acceleration of gravity.

The speed of the body increases as it goes down linearly.

This occurs because the book that receives air resistance is much heavier, so the resistance has almost no effect on its movement, the sheet does not have the air resistance because it goes down next to the book.

2) second case. Book and sheet next to each other.

In this case the book reaches the floor much earlier than the foil.

This is because the resisting force of the air has almost no effect on the book and its movement is little affected by this force.

In the case of the blade, it has very little weight, therefore as its speed increases, the resistance force of the air rapidly equals the weight of the blade.

           W_sheet - fr = 0

so after this, since the acceleration is zero, it goes down at constant speed, this speed is called the terminal velocity.

In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more.

3 0
3 years ago
a load of 400 Newton is lifted by a first class lever in which the load is at the distance of 20 cm and the effort is at the dis
Len [333]

Answer:

  1. solution,
  2. Given
  3. load =400N
  4. ld=0.2m
  5. ed=0.6m
  6. effort =150N

Explanation:

efficiency =output work/input work ×100%

l×ld/e×ed×100%

400×0.2/150×0.6×100%

80/90×100%

88.89%ans

7 0
3 years ago
Write answers with significant figures:<br>a) 17.35 g +8.498 g​
Genrish500 [490]

Answer:

25.9 g

Explanation:

= 17.35

8.498

________+

= 25.848 g = 25.85 g = 25.9 g

*so sorry if wrong

6 0
3 years ago
What is the kinetic energy of a 150 gram object moving at a velocity of 100 m/s?
Alex Ar [27]

Answer:

750 J

Explanation:

lets convert mass into kg first , 150 /1000 = 0.15 kg

kinetic energy =  \frac{mv^{2} }{2} =  \frac{0.15*100^{2} }{2}  = 750 J

3 0
3 years ago
Other questions:
  • What is the difference between a frequency polygon and an​ ogive? Choose the correct answer below.
    10·1 answer
  • can u guys help me with this question its really hard. The change in the velocity of an object is defined as its ________
    10·1 answer
  • Describe how the motions of the particles that make up an object change when the object's change when the object's temperature i
    12·1 answer
  • Which of the following rocks would most likely be found on the ocean floor
    11·2 answers
  • WHY IS SATURN ONE OF THE COLDEST PLANETS IN OUR SOLAR SYSTEM
    14·1 answer
  • The earth has a magnetic field much like a bar magnet. Explain this statement. what does a bar magnet look like? what does its f
    12·2 answers
  • A 50 kilogram woman wearing a seatbelt is traveling in a car that is moving with a velocity of +10 meters per second. In an emer
    8·1 answer
  • A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
    6·1 answer
  • American Football originated from which two sports?
    9·1 answer
  • Which of Newton's Laws does this represent? Support your choice.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!