Answer:
See Explanation
Explanation:
Given

Solving (a): Units and dimension of 
From the question, we understand that:
--- length
--- time
Remove the other terms of the equation, we have:

Rewrite as:

This implies that
has the same unit and dimension as 
Hence:
--- dimension
Length (meters, kilometers, etc.)
Solving (b): Units and dimension of 
Remove the other terms of the equation, we have:

Rewrite as:

Make
the subject

Replace s and t with their units


Hence:
--- dimension
--- unit
Solving (c): Units and dimension of 
Remove the other terms of the equation, we have:

Rewrite as:

Make
the subject

Replace s and t with their units [ignore all constants]


Hence:
--- dimension
--- acceleration
Solving (d): Units and dimension of 
Remove the other terms of the equation, we have:

Rewrite as:

Make
the subject

Replace s and t with their units [Ignore all constants]


Hence:
--- dimension
--- unit
Solving (e): Units and dimension of 
Remove the other terms of the equation, we have:

Rewrite as:

Make
the subject

Replace s and t with their units [ignore all constants]


Hence:
--- dimension
--- unit
Solving (e): Units and dimension of 
Ignore other terms of the equation, we have:

Rewrite as:

Make
the subject

Replace s and t with their units [Ignore all constants]


Hence:
--- dimension
--- units