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3 years ago

6' radius circle how many sq feet?

1 answer:

5 0

The diameter is actually 12 feet. the area i believe is pi(radius)squared. so the area would come out to 36pi. if you want it to not be with the word pi, multiply 36 by 3.14.
i hope this helps.

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What is the total weight of the bunches of bananas that weigh 1 3\4 pounds

Lisa [10]

If it weighs 1 3/4 lb’s then that’s it’s total weight…

7 0

3 years ago

The graph shows that you are traveling at a constant rate. Three of the statements are true. Which is NOT?

Bess [88]

Answer:

Your speed is 135 miles per hour.

Step-by-step explanation:

Mark me brainliest if I helped:D

7 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

3 years ago

OK so I have two questions to answer. So the first picture is question five in the second picture is question six.

Vesnalui [34]

Answer:

The slope is 2.25

The y-intercept is 3

Step-by-step explanation:

Assuming from the cut off picture, that we need to find the slope of ...

y=2.25x +3

y=mx+b form makes it easy to identify the slope and the y-intercept.

m is the slope and b is the y-intercept. Anything number that is in place of m, is the slope; and any nother in place of b is the y-intercept.

In that case, 2.25 is the slope and 3 is the y-intercept

3 0

3 years ago

Complete the squar3

cricket20 [7]

9514 1404 393

Answer:

4
-2
4
2
-2±√2

Step-by-step explanation:

In order to fill the first blank, we need to look at the second line to see what the coefficient of x is.

1. x² + 4 x +2 = 0

The constant is subtracted from both sides to get the second line.

2. x² +4x =  -2 

The value that is added on the third line is the square of half the x-coefficient: (4/2)² = 4

3. x² +4x + 4  = -2 +4

On the fourth line, the left side is written as a square, and the right side is simplified. The square root is taken of both sides.

4. √(x +2)² = ±√ 2 

Finally, 2 is subtracted from both sides to find the values of x.

5. x =  -2 ±√2 

8 0

3 years ago