Answer:
Check the explanation
Step-by-step explanation:
Here we have to first of all carry out dependent sample t test. consequently wore goggles first was selected at random for the reason that the reaction time in an emergency taken with goggles would be greater than the amount of reaction time in an emergency taken with not so weakened vision. So that we will get the positive differences d = impaired - normal
b)
To find 95% confidence interval first we need to find sample mean and sample sd for difference d = impaired minus normal.
We can find it using excel that is in the first attached image below,
Therefore sample mean
= 0.98
Sample sd
= 0.3788
To find 95% Confidence interval we can use TI-84 calculator,
Press STAT ----> Scroll to TESTS ---- > Scroll down to 8: T Interval and hit enter.
Kindly check the attached image below.
Therefore we are 95% confident that mean difference in braking time with impaired vision and normal vision is between ( 0.6888 , 1.2712)
Conclusion : As both values in the interval are greater than 0 , mean difference impaired minus normal is not equal to 0
There is significant evidence that there is a difference in braking time with impaired vision and normal vision at 95% confidence level .
Answer:
One milliampere is equal to 0.001 ampere.
Step-by-step explanation:
Mili, refers to thousandth. (for example, millimeter or milliliter.)
Answer: 11
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Explanation:
To find the inverse, or f^-1 of a function, you first replace the y= 6x-4 with x=6y-4
Finding the inverse from here is basically just finding y in terms of x.
1) x=6y-4
2) x+4=6
3) (x+4)/6= y
y= (x+4)/6 is now your f^-1.
Now that you have your inverse, replace 62 with your x in y=(x+4)/6
1) (62+4)/6
2) 66/6
3) 11
Therefore, f^-1(62)= 11
Hope this helps :)
Answer:
should be c
Step-by-step explanation:
when you count the boxes (units) you get 6 so segment AB should be 6 units long
V(x) = (2x - 3)/(5x + 4) The domain is all Real numbers except x = -4/5, because if x = -4/5 the denominator would be zero and you cannot divide by zero.{x | x ∈ R, x ≠ -4/5} w(x) = (5x + 4)/(2x - 3)similarly, x ≠ 3/2so, {x| x ∈ R, x ≠ 3/2}