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MatroZZZ [7]
3 years ago
15

My brain is too tired to function someone save me

Mathematics
1 answer:
lina2011 [118]3 years ago
5 0

Answer:

(3,2)

Step-by-step explanation:

Hope I helped

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What is 2. 3/6 +1/6 +1 2/3
Kaylis [27]
3/6+1/6+1 2/3
Make 1 2/3 into an improper fraction:
5/3
Give them all common denominators by multiplying both sides of 5/3 by 2:
10/6
Then the question becomes:
3/6+1/6+10/6
Now you add the numerators and the denominator stays the same:
14/6
Now you can simplify by dividing both sides by 2:
7/3
Now you can make it a mixed number:
2 1/3

Hope this helps :)
8 0
3 years ago
Read 2 more answers
(2.03)
ExtremeBDS [4]
Step 3 is the frist incorrect step it should be: 2x-3=3 or 2x-3=-3
3 0
3 years ago
Read 2 more answers
Evaluate the expression when m=-6.<br> 2<br> m + 5m - 4
Brums [2.3K]

Answer:

2

Step-by-step explanation:

m^2 + 5m - 4

Let m = -6

( -6) ^2 + 5(-6) -4

Exponents first

36 + 5(-6) -4

Then multiply

36 -30 -4

Then subtract

6 -4

2

5 0
3 years ago
Which is an example of Identity Property of Addition?
AURORKA [14]

Answer:

b

Step-by-step explanation:

because we can not some times change the places in addition so b is the correct answer

8 0
3 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
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