Ash is the answer. Hope this helps
Answer:
def isAnagram(s1, s2):
list1=s1
list2=s2
sortedlist1 = sorted(list1)
sortedlist2 = sorted(list2)
if sortedlist1 == sortedlist2:
print(list1+ " and "+list2+ " are anagram")
else:
print(list1+ " and "+list2+ " are not anagram")
Explanation:
Here is a call to the function isAnagram():
list1 =input("Enter String1 ")
list1 =input("Enter String2 ")
isAnagram(list1,list2)
Attached is the run and output for this program
Answer:
Just answer everyones questions and youll be at the right rank in no time
Explanation:
Answer: Option D -- Sorting an already sorted array of size n with quicksort takes O(n log n) time.
Explanation:
Sorting an already sorted array of size n with quicksort takes O(n log n) time is true about sorting functions while other options are wrong.
Based on the above, the type of security is illustrated in this example is known as data security.
<h3>What is Data security?</h3>
This is known to be the act of keeping safe data from unauthorized access and its corruption in all of its lifecycle.
Note that in the case above, the intruder is interested in the companies data and as such, the type of security is illustrated in this example is known as data security.
Learn more about security from
brainly.com/question/15668437
#SPJ1
