Answer:
E)nXML
Explanation:
XML is a short for Extensible Markup Language. It is a markup language like the Hypertext markup language (HTML) and are both used in the development of web applications. However while the HTML describes the content of the Web page that is the graphics, images and videos and how they are displayed, the XML handles the description of data and information formats, their storage and the transportation and sharing over the internet.
I think its the new age either that or end times
Answer:
1. The reason hunting seasons are displayed all over the world in cave paintings is because of the necessity to hunt. Ancient people everywhere were nomads that relied on wild animals for the majority of their calories. The paintings likely served as an expression of the importance of hunting to their culture. It could have also been used as educational material for very young children to learn about hunting as well as its importance to their community.
Explanation:
I can't do 2nd because the image was cut off, sorry.
Answer:
The page field is 8-bit wide, then the page size is 256 bytes.
Using the subdivision above, the first level page table points to 1024 2nd level page tables, each pointing to 256 3rd page tables, each containing 64 pages. The program's address space consists of 1024 pages, thus we need we need 16 third-level page tables. Therefore we need 16 entries in a 2nd level page table, and one entry in the first level page table. Therefore the size is: 1024 entries for the first table, 256 entries for the 2nd level page table, and 16 3rd level page table containing 64 entries each. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 2 (one second-level paget table) + 16 * 64 * 2 (16 third-level page tables) = 4608 bytes.
First, the stack, data and code segments are at addresses that require having 3 page tables entries active in the first level page table. For 64K, you need 256 pages, or 4 third-level page tables. For 600K, you need 2400 pages, or 38 third-level page tables and for 48K you need 192 pages or 3 third-level page tables. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 3 * 2 (3 second-level page tables) + 64 * (38+4+3)* 2 (38 third-level page tables for data segment, 4 for stack and 3 for code segment) = 9344 bytes.
Explanation:
16 E the answer
