Round pan volume is:
3.14•r^2•h
D=7 so r=3.5 in
3.14• (3.5^2)•2 = 76.97 in^3
Rec. pan vol. is :
9•6•2= 108 in^3
Rec. Pan is larger because 108 in^3 is > 76.97 in^3 :) .
The icing that will be needed to frost the round cake pan is:
We need to find the surface area:
S.A= 3.14r^2 + 2 • 3.14•r • h .... 3.14 is the value of PI
So, S.A= 3.14• 3.5^2 + 6.28• 3.5• 2= 82.47 in^2 the icing that'll be needed to frost the round cake pan.
Icing that will be needed for the rec. cake pan is:
2•9•2=36 in^2
6•9•2= 108in^2
6•2= 12 in^2
S.A= 156 in^2 the icing needed to frost the rec. cake pan .... the S.A of all sides except the bottom one :).
Good luck ;-)
The period of the function can be calculated using <span><span><span>2π</span><span>|b|</span></span><span><span>2π</span><span>|b|</span></span></span>.Period: <span><span><span>2π</span><span>|b|</span></span><span><span>2π</span><span>|b|</span></span></span>Replace <span>bb</span> with <span>11</span> in the formula for period.Period: <span><span><span>2π</span><span>|1|</span></span></span>
Answer: the circumference is the perimeter of a circle or ellipse. That is, the circumference would be the arc length of the circle, as if it were opened up and straightened out to a line segment. More generally, the perimeter is the curve length around any closed figure.
1
Add the numbers
(
−
4
+
5
)
−
(
6
+
7
)
=
0
({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}
(−4+5)−(6+7)=xx0
(
1
)
−
(
6
+
7
)
=
0
({\color{#c92786}{1}})-(6+7)=xx^{0}
(1)−(6+7)=xx0
2
Add the numbers
1
−
(
6
+
7
)
=
0
1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}
1−(6+7)=xx0
1
−
(
1
3
)
=
0
1-({\color{#c92786}{13}})=xx^{0}
1−(13)=xx0
3
Multiply the numbers
1
−
1
⋅
1
3
=
0
1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}
1−1⋅13=xx0
1
−
1
3
=
0
1{\color{#c92786}{-13}}=xx^{0}
1−13=xx0
4
Subtract the numbers
1
−
1
3
=
0
{\color{#c92786}{1-13}}=xx^{0}
1−13=xx0
−
1
2
=
0
{\color{#c92786}{-12}}=xx^{0}
−12=xx0
5
Combine exponents
−
1
2
=
0
-12={\color{#c92786}{xx^{0}}}
−12=xx0
−
1
2
=
1
-12={\color{#c92786}{x^{1}}}
−12=x1
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Solution
−
1
2
=
1