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BlackZzzverrR [31]
3 years ago
12

Match each decimal number to the correct scientific notation. 30,700 0.000307 0.00000307 3,070,000 3.07 × 10-6 arrowRight 3.07 ×

106 arrowRight 3.07 × 10-4 arrowRight 3.07 × 104 arrowRight
Chemistry
2 answers:
ss7ja [257]3 years ago
8 0

Answer:

3.07 × 10^4=30,700

3.07 × 10^-4=0.000307

3.07 × 10^-6=0.00000307

3.07 × 10^6=3,070,000

Explanation:

patriot [66]3 years ago
6 0

Answer:

  1. 30,700 = 3.07\times 10^4
  2. 0.000307 =3.07\times 10^{-4}
  3. 0.00000307 = 3.07\times 10^{-6}
  4. 3,070,000 = 3.07\times 10^6

Explanation:

Scientific notation: It is the representation of expressing the numbers which are too big or too small by representing them in decimal form with one digit before the decimal point times 10 raise to the power.

For example : 6,000,000 is written as 6.0\times 10^6

  1. 30,700 = \frac{10^4}{10^4}30,700=3.07\times 10^4
  2. 0.000307 =\frac{000307}{10^6}= 3.07\times 10^{-4}
  3. 0.00000307 = \frac{00000307}{10^8}= 3.07\times 10^{-6}
  4. 3,070,000 = \frac{10^6}{10^6 }\times 3,070,000=3.07\times 10^6
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torisob [31]

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Because the value of K is huge.

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The equilibrium reaction can be characterized by an equilibrium constant, which is the ratio of the concentration of the products by the concentration of the reactants.

Because the constant K is extremely large (10¹³) we can conclude that the concentration of the product will be greater than the concentration of the reactant, in the equilibrium. It means that the concentration of the enol will be greater.

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3 years ago
What is not a reason why actual yield is less than theoretical yield?​
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Answer:

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practical losses during the experiment

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4 0
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A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 385.mg of oxalic acid H2
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Answer:

The molarity of the sodium hydroxide solution is 0.0692 M

Explanation:

<u>Step 1: </u>Data given

Mass of H2C2O4 = 385 mg = 0.385 grams

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Volume of NaOH = 123.7 mL = 0.1237 L

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<u>Step 2</u>: The balanced equation

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<u>Step 3:</u> Calculate moles H2C2O4

Moles H2C2O4 = mass H2C2O4 / molar mass H2C2O4

Moles H2C2O4 = 0.385 grams / 90.03 g/mol

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Molarity H2C2O4 = 0.00428 moles / 0.250 L

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<u>Step 5:</u> Calculate molarity of NaOH

2*Ca*Va = n*Cb*Vb

⇒ with Ca = Molarity of H2C2O4 = 0.01712 M

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⇒ Vb = volume of NaOH = 0.1237 L

Cb = (2*0.01712*0.250)/0.1237

Cb = 0.0691 M

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