The number of years required for 1/4 cobalt-60 to remain after decay is calculated as follows
after one half life 1/2 of the original mass isotope remains
after another half life 1/4 mass of original mass remains
therefore if one half life is 5.3 years then the years required
= 2 x 5.3years = 10.6 years
Noble gases are supposed to be the least reactive elements so I’m assuming Neon would be the most least reactive out of all of them.
The correct answer is A.) Volatile. please mark brainliest (: