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AlladinOne [14]
3 years ago
15

An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate.

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
5 0

<u>Answer:</u> The net ionic equation contains Ca^{2+}(aq.) ions

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium sulfate and calcium nitrate is given as:

(NH_4)_2SO_4(aq.)+Ca(NO_3)_2(aq.)\rightarrow CaSO_4(s)2NH_4NO_3(aq.)

Ionic form of the above equation follows:

2NH_4^{+}(aq.)+SO_4^{2-}(aq.)+Ca^{2+}(aq.)+2NO_3^{-}(aq.)\rightarrow CaSO_4(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonia and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Ca^{2+}(aq.)+SO_4^{2-}(aq.)\rightarrow CaSO_4(s)

Hence, the net ionic equation contains Ca^{2+}(aq.) ions

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2. Extract the relevant information from the question: NaOH V = 30 mL , M = 0.10 M HCl V = 25.0 mL, M = ?
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Answer:

0.12M

Explanation:

A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

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From the above equation,

nA (mole of the acid) = 1

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Data obtained from the question include:

Vb (volume of the base) = 30mL

Mb (Molarity of the base) = 0.1M

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Ma (Molarity of the acid) =?

The molarity of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

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The molarity of the acid is 0.12M

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3 years ago
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