Answer:
......... idk use a cheat and look up the answer just helping
Oxygen because it is one the table of elements and none of the others are.
Answer: pH = 2,897 , basic![[H+][OH-] = 10^{-14} ==> [H+] = \frac{10^{-14}}{7,89*10^{-12} } =\frac{1}{789} \\pH= -lg([H+]) = 2,897 \\pH basic](https://tex.z-dn.net/?f=%5BH%2B%5D%5BOH-%5D%20%3D%2010%5E%7B-14%7D%20%3D%3D%3E%20%5BH%2B%5D%20%3D%20%5Cfrac%7B10%5E%7B-14%7D%7D%7B7%2C89%2A10%5E%7B-12%7D%20%7D%20%3D%5Cfrac%7B1%7D%7B789%7D%20%5C%5CpH%3D%20-lg%28%5BH%2B%5D%29%20%3D%202%2C897%20%5C%5CpH%3C7%20%3D%3D%3E%20basic)
Explanation:
(a) The mass of hydrogen sulfide produced in the reaction is 9.44 g.
(b) Water is the limiting reagent in the given reaction.
<h3>
Mass of hydrogen sulfide produced</h3>
Al2S3 + 6H2O ---> 2Al(OH)3 + 3H2S
mass of water in the reaction = 6(18 g/mol) = 108 g/mol
mass of hydrogen sulfide in the reaction: = 3(34) = 102 g/mol
108 g/mol of H2O ------- > 102 g/mol of H2S
10 of H2O -----------> ?
= 9.44 g
Aluminum sulfide will be completely consumed by the reaction while some fraction of water will remain. Thus, water is the limiting reagent in the given reaction.
Learn more about limiting reagents here: brainly.com/question/26905271
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