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olya-2409 [2.1K]
3 years ago
6

How many liters of 4M solution can be made using 100 grams of lithium bromide

Chemistry
1 answer:
uysha [10]3 years ago
5 0
Molar mass of LiBr (mm )= 86.845 g/mol

Molarity ( M ) = 4 M 

Mass of solute ( m ) = 100 g

Volume ( V ) = in liters ?

V = m / mm  * M

V = 100 / 86.845 * 4

V = 100 / 347.38

V = 0.2875 L

hope this helps!.
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If two clear liquids are mixed and a precipitate formed, what has probably happened?
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May someone assist, please...? I don't know how to do chemistry work...
EastWind [94]

Answer:

1) 90.0 mL

2) 11.25 M

3) 0.477 M

4) 144 mL

Explanation:

The main formula that will be used for all these calculations is:

                                                     C₁V₁ = C₂V₂

C stands for concentration and V stands for volume and the subscripts 1 and 2 indicate an initial concentration or volume and a final concentration or volume.

For each problem, it's best to start by figuring out what you have and what you need to find. Figure out if you're looking for an initial value or a final value.

1) We need to find the initial volume. So, take what values you have and plug them in and then solve for whatever variable:

5.00 M · V₁ = 500.0mL · 0.900 M                        - divide by 5.00

C₁ = 90.0 mL

2) This time we're finding the initial concentration:

20.0mL · C₁ = 150.0mL · 1.50 M                          - divide by 20.0mL

C₂ = 11.25 M

3) Now we're finding the final concentration:

12.00mL · 3.50 M = 88.0mL · C₂                         - divide by 88.0mL

C₂ = 0.477 M

4) Finally, we're looking for the final volume:

9.0mL · 8.0 M = 0.50 M · V₂                                - divide by 0.50 M

V₂ = 144mL

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3 years ago
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Gases A and B are confined to a cylinder and piston and react to form product C. As the reaction occurs, the system loses 1189 J
aliya0001 [1]

Answer:

The change in the internal energy of the system -878 J

Explanation:

Given;

energy lost by the system due to heat, Q = -1189 J (negative because energy was lost by the system)

Work done on the system, W = -311 J (negative because work was done on the system)

change in internal energy of the system, Δ U = ?

First law of thermodynamics states that the change in internal energy of a system (ΔU) equals the net heat transfer into the system (Q) minus the net work done by the system (W).

ΔU = Q - W

ΔU = -1189 - (-311)

ΔU = -1189 + 311

ΔU = -878 J

Therefore, the change in the internal energy of the system -878 J

8 0
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