Answer:
Explanation:
% yields = <u>experimental yields</u> / theoretical yields )x 100%
=( 302 ÷ 320 )x 100% = 94.4 %
% error = 100% - 94.37% 5.64%
or u can use this law :
% error =(theoretical value - experimental value )/ theoretical value) x 100%
( 320 - 302 )/ 320 ) x 100% = 5.64%
Answer:
10/9
Explanation:
First, let's convert 1/3 and 7/9 so that the have the same denominator. To do this let's find the least common multiple of 3 and 9.
List the multiples of 3 and 9:
3: 3, 9
9: 9
They have a least common multiple of 9
We need to convert 1/3 so it has a denominator of 9:
1/3*3/3 (we can multiply it by 3/3 because any number over itself is 1) = 3/9
s-3/9=7/9
Add 3/9 to both sides to isolate s
s=10/9
The variable "air pressure inside the football" in this experiment is quantitative and dependent variable. Hence, option D is correct.
<h3>What is the dependent variable?</h3>
The dependent variable is the variable that is being measured or tested in an experiment.
In the experiment, the scientist filled the footballs with fix quantity of pressure which was then kept for 12 hours. After 12 hours the pressure inside the footballs was again measured. Pressure here is a quantitative variable.
Since the air temperature is an independent variable. The pressure being the dependent variable depends upon the temperature of the air.
Independent variable; The variable which does not depends upon any other variable.
Dependent variable; The variable which depends upon the independent variable or varies with the change independent variable.
Qualitative variables are variables which cannot be expressed in form of numbers. They generally convey the characteristic, category, quality or type.
Whereas Quantitative variables are the variables which can be expressed in the form of numbers. These are the variables which exist along the continuous sequence.
Learn more about dependent variables here:
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Sodium, hydrogen, carbon, and oxygen
The value of Keq = 110
Let's know how to get it :
According to the equilibrium reaction equation :
I2(g) + Br2(g) → 2IBr(g)
now we need to get the value of Keq
when the Keq expression is:
Keq = [IBr]^2/ [I] [Br]
when we have [IBr] at equilibrium = 0.84 so we need to get [I] &[Br] at equilibrium .
when [Br2] = [I2] = 0.5 - 0.84 / 2
= 0.08 M
so, by substitution
∴ Keq = (0.84)^2/(0.08)^2
= 110
