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Rufina [12.5K]
2 years ago
12

A mixture of 15.0 g of aluminum sulfide and 10.0 g of water reacts according to the following equation:

Chemistry
1 answer:
masha68 [24]2 years ago
8 0

(a) The mass of hydrogen sulfide produced in the reaction is 9.44 g.

(b) Water is the limiting reagent in the given reaction.

<h3>Mass of hydrogen sulfide produced</h3>

Al2S3 + 6H2O ---> 2Al(OH)3 + 3H2S

mass of water in the reaction = 6(18 g/mol) = 108 g/mol

mass of hydrogen sulfide in the reaction: = 3(34) = 102 g/mol

108 g/mol of H2O ------- > 102 g/mol of H2S

10 of H2O -----------> ?

= 9.44 g

Aluminum sulfide will be completely consumed by the reaction while some fraction of water will remain. Thus, water is the limiting reagent in the given reaction.

Learn more about limiting reagents here: brainly.com/question/26905271

#SPJ1

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