PART A)
Here by force balance along Y direction
Force balance along X direction
now by torque balance
PART B)
now from above equations
now net reaction force of wall is given as
Number one- the pendelum slowly reduces energy and eventually loses everything and will stand still.
Number two- I can account due to the factor of it repeating the same result
<span>A continuous spectrum is one where the light emitted goes along the entire spectrum. A line spectrum is one that only emits a few frequencies. </span>
Answer:
ω' = 0.815 rad/s
Explanation:
Given,
R = 1.20 m
Inertia of merry-go- round= 240 kg.m²
Rotating speed = 9 rpm =
=0.9424 rad/s
mass of the child, m = 26 kg
angular speed of the merry-go-round=?
we know
Angular momentum, L = I ω
Moment of inertia of the child
I' = m r² = 26 x 1.2² = 37.44 kgm²
Conservation of angular momentum
initial angular momentum = Final angular momentum
I ω = (I+I')ω'
240 x 0.9424 = (240+37.44) ω'
226.176= 277.44 ω'
ω' = 0.815 rad/s
new angular speed of the merry-go- round is equal to 0.815 rad/s
Answer:
Given Acousting power P=2.35*10^5W
Distance r=51.3m
Area=4πr^2=4*3.142*51.3^2=33075.08
Sound intenstity I= (2.35*10^5)/33075.08=6962.8W/m^Reference sound intenstity Io=10^-12w/m^2
Sound intenstity I1=10*log(I/Io)
10*log(6962.8/10^-12)db =24.5w/m^2