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Alexus [3.1K]
3 years ago
9

C 2000 pascals

Physics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

C. bottle opener

B. Force x distance

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B.b 70 would be the answer
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ayo 20 m long is heated from a temperature of 5 degree celsius to 55 degree celsius if the change in length is 0.020 m calculate
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Answer:2 x 10^-5K^-1

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1. Of the following, the one that is not an example of a suspension is
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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between
Klio2033 [76]

Answer:

a) u=0.05602\ m.s^{-1}

b) u'=0.0169\ m.s^{-1}

Explanation:

Given:

mass of the ball, m=0.4\ kg

horizontal velocity of the ball, u=10\ m.s^{-1}

mass of the person, M=71\ kg

a)

<u>Using the law of  conservation of momentum:</u>

m.v=(M+m).u

0.4\times 10=(71+0.4)\times u

u=0.05602\ m.s^{-1}

b)

Given:

  • rebound velocity of the ball, v'=7\ m.s^{-1}

Using conservation of momentum,

m.v+M.u=m.v'+M.u'

0.4\times10+71\times 0=0.4\times 7+71\times u'

u'=0.0169\ m.s^{-1}

4 0
3 years ago
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If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
Mrrafil [7]

The magnitude of the electric field at this location is 1.5\times 10^{10} N/C

<u>Explanation:</u>

Given

Charge\ of\ the\ particle\ Q=4.3\times 10^-18\ C\\Force\ with\ which\ it\ is\ attracted\ F=6.5\times 10^-8\ N

Electric field at this location determined by the force and charge.

E=F/Q

E=\frac{6.5\times 10^-8}{4.3\times10^-18} =1.5\times\ 10^{10}  \ N/C

7 0
4 years ago
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