a space probe with a mass of 4000 kg expels 3,500 of its mass at a velocity of 2000 m/s. what is the velocity of the remaining 5
1 answer:
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Answer
given,
Tension of string is F
velocity is increased and the radius is not changed.
the string makes two complete revolutions every second
consider the centrifugal force acting on the stone
=
now centrifugal force is balanced by tension
T =
From the above expression we can clearly see that tension is directly proportional to velocity and inversely proportional to radius.
When radius is not changing velocity is increasing means tension will also increase in the string.
Answer: A- It would increase
Explanation:
According to the law of universal gravitation:
Where:
is the module of the attraction force exerted between both objects
is the universal gravitation constant.
and
are the masses of both objects
is the distance between both objects
As we can see, the gravity force is directly proportional to the mass of the bodies or objects and inversely proportional to the square of the distance that separates them.
In other words:
<h2>If we decrease the distance between both objects, the gravitational force between them will increase. </h2>Answer:
The force, exerted by Big Ben on the Empire State Building is 2.66972 × 10⁻⁷ N
Explanation:
The question relates to the force of gravity experienced between two bodies
The given parameters are;
The mass of Big Ben, M₁ = 1 × 10⁸ kg
The mass of the Empire State Building, M₂ = 1 × 10⁹ kg
The distance between the two Big Ben and the Empire State Building, r = 5,000,000 meters
By Newton's Law of gravitation, we have;
Where;
F = The force exerted by Big Ben on the Empire State Building and vice versa
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
M₁, M₂, and r are the given parameters
By plugging in the values of the parameters and the constant into the equation for Newton's Law of gravitation, we have;
The force, 'F', exerted by Big Ben on the Empire State Building is F = 2.66972 × 10⁻⁷ N.