The general formula is:
-- (A)
Where g = 9.8 m/s/s
= 0
= 100
a)
Time=t=3s.
Plug-in the values in (A)
y = 100 -(1/2*9.8*3*3)
y = 100-44.1 = 55.9m
Height of the ball exactly after 3 seconds = 55.9m.
b)
At ground, y=0; Plug-in values in (A):
A=> 0 = 100 - (1/2* 9.8 * [tex]t_{2}[/text])
Therefore t = + 4.52 s and - 4.52 seconds.
As t cannot be negative, therefore:
Time when ball hits the ground =
4.52s
-i
Answer:
F(x) plus or minus would shift up or down...
1/3 f(x) "shrinks everything down by 1/3
the first answer is the correct choice
Step-by-step explanation:
Here's some guidelines to help you:
For 1, 4, 5, and 6, they are 30-60-90 triangles. What's that you may ask? Well, it means that the sides have a predetermined length when one side is given. In #1 for example, you have a side of 11sqrt3, this means that "n" is 11 because in a 30-60-90 triangle, the longer side is the sqrt3 times the length of the shorter side. So to get the shorter side, we divide by sqrt3 to get 11. "m", or the hypotenuse, can be determined by taking twice the length of the shorter side. Since we figured out earlier that the shorter side is 11, 11 times 2 is 22. So the answer for #1 is n=11, m=22.
For 2 and 3, they are 45-45-90 triangles, triangles where the two lengths are the same and the hypotenuse is either leg length times sqrt2. In problem #2 for example, "y" must be 17 because one leg length is 17. "x", or the hypotenuse, is equal to 17sqrt(2) because 17 times sqrt(2).
You can apply all these rules to the other 4 problems I didn't explain.
Hope this long explanation clears your doubts!
Answer: 3.852
Step-by-step explanation:give me brianlest
Hey, I can answer in the comments but you need to have the boxes down in the picture if you can tell me the multiple degrees it has in the boxes then I can help thx :)
