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2 years ago

Find the range of the function shown on the grid. "Brainliest only if correct"

Mathematics

1 answer:

kicyunya [14]2 years ago

6 0

Answer:

Step-by-step explanation:

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Four more than twice a number is -10

Anna [14]

Answer:

-7

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75 at

satela [25.4K]

The total cost is the dependant variable and the number of tickets along with flat out price is the independent variable.

The equation would be y = 1.25x + ?

You would insert 25 for x which equals 31.25 and insert 43.75 for y.

43.75 = 31.25 + ? Then subtract 31.25 from both sides of the equation and you would get....

12.5 = ?

That is your flat rate to get in to the fair

7 0

3 years ago

Gary wanted to determine the average height of boys at the high school. His older brother is on the basketball team, so he asked

fomenos

Answer:

The answer would be "no because boys on the basketball team are likely to be taller than other boys at the school"

Step-by-step explanation:

Hope this helps:)...if not then sorry for wasting your time and may God bless you:)

5 0

2 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago

F(x)=3/5x+1 find f(-15)

Luda [366]

Nothing hahahahahah

3 0

3 years ago