All categories

3 years ago

Work = force x distance

Physics

1 answer:

Nadya [2.5K]3 years ago

6 0

Answer:

horse power of the truck 39,000 kgm²s⁻³

Explanation:

Calculate horse power of the truck.

Work = force x distance

where, force = mg = 2000 kg x 9.8 m/s² = 19,600 kgm/s²

distance = 10 meter

Work = 19,600 kgm/s² x 10 meter

= 196,000 kgm²s⁻²

Power = work / time

= 196,000 kgm²s⁻² / 5 seconds

= 39,000 kgm²s⁻³

You might be interested in

Distance from any point on a wave to an identical point on the next wave?

lesantik [10]

It's called the "Wavelength". It corresponds to <span>the distance from any point on a wave to an identical point on the next wave and could also be from crest to crest or trough to trough.

Hope this helps !

Photon</span>

6 0

3 years ago

How high up is a 5kg object that has 300j of energy

Eddi Din [679]

-- If the object is moving with speed of 10.954 meters per second, then
it has 300J of kinetic energy no matter where it may be located.

-- If the object is 6.118 meters above somewhere, then it has 300J of
gravitational potential energy relative to that place.

7 0

3 years ago

On Planet Y, which has no air, a dropped object falls 9 m in 3 seconds. What is g, the acceleration due to gravity, on that plan

slavikrds [6]

Answer:

a = 2 m/s^2

which agrees with the third answer option provided.

Explanation:

Recall the kinematic formula for displacement under the action of a constant acceleration "a":

yf - yi = 1/2 a t^2

using the information provided this equation becomes:

9 = 1/2 a (3)^2

solve for a:

9 * 2 / 9 = a

then a = 2 m/s^2

which agrees with the third answer option provided.

7 0

3 years ago

Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

tester [92]

Answer: $40\ N/C$

Explanation:

Given

Magnitude of charge is $q=0.5\ C$

Force experienced is $F=20\ N$

Electric field intensity is the electrostatic force per unit charge

$\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C$

Thus, the electric field intensity is $40\ N/C$

6 0

3 years ago

What is the frequency of light with a wavelength of 7.9 x 10^-9 m? ( the speed of light is 3.00 x 10^8)

nlexa [21]

Using the formula v=f times lambada
then v=the speed of light.
and f=what’s we’re looking for
and lambada=the wavelength.

so then you sub what you have (v and lambada) in the formula.
then multiply the frequency(f) by the given wavelength and then solve for f

3 0

3 years ago