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rjkz [21]
3 years ago
6

In a game of tug of war, team one pulls to the right with a force of 500 newtons and team two pulls to the left with a force of

600 newtons. What is the net force?
Physics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

Explanation:

There is no set way to do this. All you have to do is define left and right. Left will be minus and right will be the opposite --- plus.

That is completely arbitrary. It could be the other way around. It does not matter.

Left is minus so: - 600 N   is the force going left.

Right plus so: + 500 N

Now just add.

Net Force = +500 - 600

Net Force = - 100 N

So the Net Force is - 100 N going to the left.

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A peregrine falcon dives at a pigeon. The falcon starts with zero downward velocity and falls with the acceleration of gravity.
Reptile [31]

Answer:

t = 3.94 s

Explanation:

This can be modeled as a case of free fall motion. Because, the falcon is going down with acceleration, that is equal to acceleration due to gravity. To find the time taken by the falcon to intercept the pigeon, we will use second equation of motion for vertical direction:

h = v_{i}t + \frac{1}{2}gt^2

where,

h = height = 76 m

vi = initial speed of falcon = 0 m/s

t = time required = ?

g = acceleration due to gravity = 9.81 m/s²

Therefore,

76\ m = (0\ m/s)(t) + \frac{1}{2}(9.81\ m/s^2)t^2\\t^2 = \frac{(2)(76\ m)}{9.8\ m/s^2}\\\\t = \sqrt{ 15.49\ s^2}\\

<u>t = 3.94 s</u>

5 0
3 years ago
Light passes from a material A, which has an index of refraction of 4/3, into material B, which has an index of refraction of 5/
katrin2010 [14]

Answer:

(b) 32.2°

Explanation:

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 30.0° )

{\theta_r} is the angle of refraction  ( ? )

{n_r} is the refractive index of the refraction medium  (Material B, n=5 / 4)

{n_i} is the refractive index of the incidence medium (Material A, n=4 / 3)

Hence,  

{\frac {4}{3}}\times {sin30.0^0}={\frac {5}{4}}\times{sin\theta_r}

Angle of refraction = sin^{-1}0.5333 = 32.2°

5 0
4 years ago
An apple dropped from the branch of a tree hits the ground in 0.5 s. If the acceleration of the apple during its motion is 10 ms
Ipatiy [6.2K]

Given that,

Time = 0.5 s

Acceleration = 10 m/s²

(I). We need to calculate the speed of apple

Using equation of motion

v=u+at

Where, v = speed

u = initial speed

a = acceleration

t = time

Put the value into the formula

v=0+10\times0.5

v=5\ m/s

(III). We need to calculate the height of the branch of the tree from the ground

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value into the formula

s=0+\dfrac{1}{2}\times10\times(0.5)^2

s=1.25\ m

(II). We need to calculate the average velocity during 0.5 sec

Using formula of average velocity

v_{avg}=\dfrac{\Delta x}{\Delta t}

v_{avg}=\dfrac{x_{f}-x_{i}}{t_{f}-t_{0}}

Where, x_{f}= final position

x_{i} = initial position

Put the value into the formula

v_{avg}=\dfrac{1.25+0}{0.5}

v_{avg}=2.5\ m/s

Hence, (I). The speed of apple is 5 m/s.

(II). The average velocity during 0.5 sec is 2.5 m/s

(III). The height of the branch of the tree from the ground is 1.25 m.

7 0
3 years ago
A pair of bullocks exerts a force of 140 N on a plough. The field being ploughed is 15 m long. How much work is done in ploughin
Dahasolnce [82]

Answer:

2100 J

Explanation:

Work = force × distance

W = Fd

W = (140 N) (15 m)

W = 2100 J

3 0
4 years ago
Read 2 more answers
If an object that weighs 20 N is lifted from the ground to a
Radda [10]

Answer:

false 20 n x 0.32 m = 6.4 J

3 0
4 years ago
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