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3 years ago

What will occur when the trough of wave A overlaps the trough of wave B?

Physics

2 answers:

olganol [36]3 years ago

5 0

Answer:

Constructive interference

Explanation:

The superposition of two wave is called interference phenomenon. After interference of wave, the amplitude of resultant wave can be more, less or remains the same.

The two conditions of interference are :

1. Constructive interference 2. Destructive interference

According to given question, when the trough of wave A overlaps the trough of wave B constructive interference occurs. The amplitude of resultant wave is greater than the individual waves. Also, the energy of the resultant wave is more than the energies of wave A and wave B.

densk [106]3 years ago

3 0

Constructive interference will occur, which means the waves will combine.

In destructive inference, the waves cancel each other out.

Hope this helps :)

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Find the resistance of a stereo: current is 7 A voltage is 49 V.

pochemuha

Answer:

R = 7 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance. In this way, we have the following equation.

V = I*R

where:

V = voltage = 49 [V] (units of volts)

I = current = 7 [amp] (amperes)

R = resistance [ohms]

Now clearing R.

R =V/I

R = 49/7

R = 7 [amp]

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3 years ago

An owl has a mass of 4.00 kg. It dives to catch a mouse, losing 800.00 J of its GPE. What was the starting height of the owl, in

vesna_86 [32]

Answer:

height =20m

Explanation:

gpe=mgh

800=4×10×x

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3 years ago

Albert Bandura emphasized the idea of __________, which is the belief one has in one’s own ability to succeed. A. operant condit

Darya [45]

Answer hopefully = C. self-efficacy

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2 years ago

Read 2 more answers

A horizontal string fixed at both ends is oscillating in a standing wave pattern. Consider the vertical motion of a point on the

Naddika [18.5K]

Answer:

All of the choices are correct except the nodes, which don't move at all.

Explanation:

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6 0

3 years ago

Problem Page Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 28. g o

sergejj [24]

Answer : The maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

Solution : Given,

Mass of $C_2H_6$ = 28 g

Mass of $O_2$ = 190 g

Molar mass of $O_2$ = 32 g/mole

Molar mass of $C_2H_6$ = 30 g/mole

Molar mass of $CO_2$ = 44 g/mole

First we have to calculate the moles of $C_2H_6$ and $O_2$ .

$\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{28g}{30g/mole}=0.933moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{190g}{32g/mole}=5.94moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

From the balanced reaction we conclude that

As, 2 mole of $C_2H_6$ react with 7 mole of $O_2$

So, 0.933 moles of $C_2H_6$ react with $\frac{7}{2}\times 0.933=3.26$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $C_2H_6$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CO_2$

From the reaction, we conclude that

As, 2 mole of $C_2H_6$ react to give 4 mole of $CO_2$

So, 0.933 moles of $C_2H_6$ react to give $\frac{4}{2}\times 0.933=1.87$ moles of $CO_2$

Now we have to calculate the mass of $CO_2$

$\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2$

$\text{ Mass of }CO_2=(1.87moles)\times (44g/mole)=82.3g$

Therefore, the maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

6 0

3 years ago