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alekssr [168]
3 years ago
14

What is the smallest part of an element? An atom

Physics
2 answers:
ratelena [41]3 years ago
4 0

Answer:

yes it is an atom

Explanation:

KatRina [158]3 years ago
3 0

Answer:

poop

Explanation:

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A taxi starts from Monument Circle and travels 5 kilometers to the east for 5 minutes. Then it travels 10 kilometers to the sout
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On the moon, a feather is dropped from a height of 1.40 m. The acceleration of gravity on the moon is -1.67 m/s2. Determine the
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1.29 s

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  • Acclⁿ due to gravity = 1.67 m/s²
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As we know that ,

\sf\longrightarrow Time_{descent}= \sqrt{\dfrac{2H}{g_{(moon)}}}\\\\\sf\longrightarrow t_d = \sqrt{\dfrac{ 2\times 1.4}{1.67}} \\\\\sf\longrightarrow t_d =\sqrt{1.67} s\\\\\sf\longrightarrow \boxed{\red{\sf Time_{descent}= 1.29 s }}

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Pls help ASAP
12345 [234]

Answer:

a. 4.733 × 10⁻¹⁹ J = 2.954 eV b i. yes ii. 0.054 eV = 8.651 × 10⁻²¹ J

Explanation:

a. Find the energy of the incident photon.

The energy of the incident photon E = hc/λ where h = Planck's constant = 6.626 × 10⁻³⁴ Js, c = speed of light = 3 × 10⁸ m/s and λ = wavelength of light = 420 nm = 420 × 10⁻⁹ m

Substituting the values of the variables into the equation, we have

E = hc/λ

= 6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s ÷ 420 × 10⁻⁹ m

= 19.878 × 10⁻²⁶ Jm  ÷ 420 × 10⁻⁹ m

= 0.04733 × 10⁻¹⁷ J

= 4.733 × 10⁻¹⁹ J

Since 1 eV = 1.602 × 10⁻¹⁹ J,

4.733 × 10⁻¹⁹ J = 4.733 × 10⁻¹⁹ J × 1 eV/1.602 × 10⁻¹⁹ J = 2.954 eV

b. i. Is this energy enough for an electron to leave the atom

Since E = 2.954 eV is greater than the work function Ф = 2.9 eV, an electron would leave the atom. So, the answer is yes.

ii. What is its  maximum energy?

The maximum energy E' = E - Ф = 2.954 - 2.9

= 0.054 eV

= 0.054 × 1 eV

= 0.054 × 1.602 × 10⁻¹⁹ J

= 0.08651  × 10⁻¹⁹ J

= 8.651 × 10⁻²¹ J

7 0
3 years ago
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