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Amiraneli [1.4K]
4 years ago
12

Please someone help ASAP! :)

Mathematics
2 answers:
mojhsa [17]4 years ago
6 0

Answer:

236.715 ft squared

Step-by-step explanation:

This figure is composed of a rectangle and two semicircles that we can just combine into one circle. Let's find the areas separately.

Circle: the two semicircles will just add up to a circle, so we'll find the area of a circle with radius 15/2 ft.

A=\pi r^2=\pi *(15/2)^2=56.25\pi ≈ 176.715 ft squared

Rectangle: the area of a rectangle is length times width; here the length is 15 and the width is 4, so A = 15 * 4 = 60 ft squared.

Now, we just add these two together:

176.715 + 60 = 236.715 ft squared

Hope this helps!

steposvetlana [31]4 years ago
5 0

Answer:

236.625

Step-by-step explanation:

2 semi circles = 1 circle

Radius = 15/2 = 7.5

Circle + Rectangle

(3.14 × 7.5²) + (15 × 4)

236.625 ft²

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Answer:

tan R= 45/28

tan S= 28/45

Step-by-step explanation:

tan R = TS/RT= 45/28

tanS = RT/TS= 28/45

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Katie is making a planter box out of boards.If her box measures 645 inches long and 359 wide , how many inches of board will she
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A weed called the boomstar vine is known for growing at a very fast rate. It can grow up to 0.5 feet per day. How fast in inches
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4 years ago
Before a computer is assembled, its motherboard goes through a special inspection. Assume only 85% of motherboards pass this ins
andreyandreev [35.5K]

Answer:

(a) The probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b) On average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

Step-by-step explanation:

Let <em>X</em> = number of motherboards that pass the inspection.

The probability that a motherboards pass the inspection is P (X) = <em>p</em> = 0.85.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is,

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that at least 13 of the next 15 motherboards pass inspection as follows:

P (X ≥ 13) = P (X=  13) + P (X = 14) + P (x = 15)

               ={15\choose 13}0.85^{13}(1-0.85)^{15-13}+{15\choose 13}0.85^{14}(1-0.85)^{15-14}\\+{15\choose 13}0.85^{16}(1-0.85)^{15-15}\\=0.2856+0.2312+0.0874\\=0.6042

Thus, the probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b)

Computed the expected number of motherboards should be inspected until a motherboard that passes inspection is found as follows:

Expected\ value=\frac{1}{p}=\frac{1}{0.85}= 1.1764\approx1.18

Thus, on average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

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