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3 years ago

How many passwords of 4 digits are there(a)if none of the digits can be repeated?(b)start with 5 and end in an even digit?

Mathematics

1 answer:

liraira [26]3 years ago

3 0

Answer:

5040,56

Step-by-step explanation:

We have to construct pass words of 4 digits

a) None of the digits can be repeated

We have total digits as 0 to 9.

4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)

No of passwords = 10P4

= $10(9)(8)(7)\\=5040$

b) start with 5 and end in even digit

Here we restrain the choices by putting conditions

I digit is compulsorily 5 and hence only one way

Last digit can be any one of 0,2,4,6,8 hence 5 ways

Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)

=56

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3 years ago

Sam takes x minutes yo walk from home to library and 5 minutes more to walk from the library to school than fron home to the lib

LuckyWell [14K]

Answer:

$2x+5\ minutes$

Step-by-step explanation:

Given:

Sam takes x minutes yo walk from home to library.

And takes 5 minutes more to walk from the library to school than from home to the library.

Express the total time taken for Sam to walk from home to school via the library in terms of x.

<u>Solution:</u>

Time taken by Sam to walk from home to library = $x\ minutes$

Time taken by Sam to walk from library to school = $x+5\ minutes$

Total time taken by Sam to walk from home to school via the library = Time taken to walk from home to library + Time taken to walk from library to school

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3 years ago

!!Plz urgent help!!

Firdavs [7]

Answer:

890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(AB)(BC)$

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

(13)² = 5² + BC²

169 = 25 + BC²

BC² = 144

BC = 12

Area of the triangular base = $\frac{1}{2}(5)(12)$

= 30 cm²

Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

= 540 cm³

Volume of one spherical bead = $\frac{4}{3}\pi r^{3}$

= $\frac{4}{3}\pi (0.525)^{3}$

= 0.606 cm³

Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

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Therefore, 890 beads can be fitted in the triangular prism.

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3 years ago

Please Answer!!!!

Morgarella [4.7K]

Answer:

A). F = $\frac{9C}{5}+32$

B). 374°F

Step-by-step explanation:

A). Formula to convert the temperature from degree centigrade to °F is,

C = $\frac{5}{9}(F-32)$

We have to solve the formula to get the value of F,

9 × C = $9\times \frac{5}{9}(F-32)$

9C = 5(F - 32)

$\frac{9C}{5}=\frac{5(F-32)}{5}$

$\frac{9C}{5}=(F-32)$

F = $\frac{9C}{5}+32$

B). In this part we have to find the value of 190° C in °F.

From the formula given in part (A),

F = $\frac{9\times 190}{5}+32$

= 374°

Therefore, 190°C = 374°F

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