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3 years ago

I don't really know how to start

Mathematics

2 answers:

patriot [66]3 years ago

6 0

4v/27 = 16
You have to get rid of the 27 in the denominator, do so by multiplying both sides by the 27.
Now you have:
4v = 432
Next you need to get rid of the 4 by dividing both sides by 4
Your answer is now:
v = 108

Art [367]3 years ago

5 0

Answer: v=108

here are the steps:
1. multiply both sides by 27. $\frac{4v}{27}$ x 27 = 16 x 27
2. refine. 4v = 432
3. divide both sides by 4. $\frac{4v}{4}$ = $\frac{432}{4}$
4. refine. v = 108

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Alex deposits ₹ 12000 in a bank for 4 1/2

pishuonlain [190]

Answer:

12780

Step-by-step explanation:

7 0

3 years ago

Use the formula for the cosine of the difference of two angles to find the exact value of the following expression.

Zolol [24]

Answer:

Exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

Step-by-step explanation:

Given:

Cos(45° - 60°)

We have to apply the formula of cosine for difference of the two angles.

Formula:

$cos(a-b)=cos(a)\ cos(b)+sin(a)\ sin(b)$

Plugging the values.

⇒ $cos(45-60)=cos(45)\ cos(60) + sin(45)\ sin(60)$

We know that the values :

$sin(45) =cos(45) = \frac{1}{\sqrt{2} }$

$sin(60)=\frac{\sqrt{3} }{2}$ and $cos(60)=\frac{1}{2}$

So,

⇒ $cos(45-60)=(\frac{1}{\sqrt{2} } \times \frac{1}{2} ) + (\frac{1}{\sqrt{2} } \times \frac{\sqrt{3} }{2})$

⇒ $cos(45-60)=(\frac{1}{2\sqrt{2} } + \frac{\sqrt{3} }{2\sqrt{2} })$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )\times \frac{2\sqrt{2} }{2\sqrt{2} }$ ...rationalizing

⇒ $cos(45-60)=\frac{2\sqrt{2} +2\sqrt{6} }{ 8}$

⇒ $cos(45-60)=\frac{2(\sqrt{2}+\sqrt{6})}{8}$ ...taking 2 as a common factor

⇒ $cos(45-60)=\frac{(\sqrt{2}+\sqrt{6})}{4}$

To find the exact values we have to put the values of sq-rt .

As, $\sqrt{2}=1.41$ and $\sqrt{6} =2.44$

Then

⇒ $cos(45-60)=\frac{( 1.41+2.44)}{4}$

⇒ $cos(45-60)=\frac{( 3.85)}{4}$

⇒ $cos(45-60)=0.96$

So the exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

3 0

3 years ago

Batman (mass=100 kg) jumps straight down from a bridge in to a boat (mass = 580 kg) in which a criminal is fleeing. The velocity

Crank

Answer:

$v_b=11.94\ m/s$

Step-by-step explanation:

Linear Momentum

The momentum of a system of masses m1,m2,m3... with speeds v1,v2,v3,... is given by

$M=m_1v_1+m_2v_2+m_3v_3+...$

When some interactions take place into the system of masses with no external forces interferring, the total momentum is not changed, which means that if the new speeds are v1', v2', v3'... then:

$m_1v_1+m_2v_2+m_3v_3+...=m_1v_1'+m_2v_2'+m_3v_3'+...$

The problem relates the story of Batman (m1=100kg) who is initially assumed at rest and lands on a boat with mass m2=580 kg initially moving at 14 m/s to the positive reference. When the collision takes place, both masses join and a common speed $v_b$ is achieved by the common mass. Applying the conservation of momentum, we have