The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
STatiana [176]
Answer:
<h3>The remainder is zero</h3>
Step-by-step explanation:
Given the polynomial function p(x)=x^3-6x^2+32, if x-4 is a factor, then <u>we can find the remainder if the polynomial is divided by x -4.</u>
First we need to equate the function x - 4 to zero and find x;
x - 4 = 0
x= 0+4
x = 4
Next is to substitute x = 4 into the expression p(x)=x^3-6x^2+32
p(x)=x^3-6x^2+32
p(4)=(4)^3-6(4)^2+32
p(4) = 64 - 96 + 32
p(4) = 0
Hence the remainder when x-4 is divided by the polynomial is zero
Answer:
256
Step-by-step explanation:
1+2+4+8+16+32+64+128+256
Answer:
=−66k4+12188
Step-by-step explanation:
Answer:
A)
Step-by-step explanation:
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